This is an example of representing a Zebra Puzzle using a Z3-based Python code: There are 5 Producers in this puzzle. Categories and possible items: - Shirt: black, green, orange, pink, red - Name: Barbara, Isabella, Jane, Nicole, Rachel - Jam: apricot, cherry, fig, raspberry, watermelon - Size: 10 oz, 12 oz, 14 oz, 20 oz, 6 oz - Source: backyard, farmers' coop, local grocer, organic farm, wild pickings Clues: - The producer whose jam comes from Wild pickings is in the fourth position. - The producer selling Cherry jam is somewhere to the right of the one wearing a Green shirt. - Isabella is selling Cherry jam. - The producer wearing a Pink shirt is somewhere between the producer whose jam source is the Backyard and the one selling Watermelon jam, in that order. - The producer selling 14 oz jars is somewhere to the right of the one wearing a Green shirt. - The producer with 14 oz jars is next to the one selling Raspberry jam. - The Raspberry jam producer is positioned at one of the ends. - Barbara is next to the producer whose jam source is the Organic farm. - Jane is located somewhere between Nicole and Isabella, in that order. - The producer of Fig jam sources the fruit from an Organic farm. - The producer with 10 oz jars is at one of the ends. - The Raspberry jam producer is somewhere to the right of the one wearing a Green shirt. - The producer with 12 oz jars is next to the one who has 6 oz jars. - Isabella is next to the producer wearing a Black shirt. - The producer with 6 oz jars is next to the one whose source is the Local grocer. - The producer with 6 oz jars is in the second position. - Rachel's source of fruit is the Farmers' coop. - Barbara is next to Nicole. - The producer wearing an Orange shirt gets her fruit from the Backyard. - The producer with 12 oz jars is in the very first position. ```python from z3 import * import json import sys # Define all categories in a single list of tuples: # (House is implicit; each row's first column will be the house number.) categories = [ ("Shirt", ["black", "green", "orange", "pink", "red"]), ("Name", ["Barbara", "Isabella", "Jane", "Nicole", "Rachel"]), ("Jam", ["apricot", "cherry", "fig", "raspberry", "watermelon"]), ("Size", ["10 oz", "12 oz", "14 oz", "20 oz", "6 oz"]), ("Source", ["backyard", "farmers' coop", "local grocer", "organic farm", "wild pickings"]) ] # No need to change here, automatically processing NUM_POSITIONS = len(categories[0][1]) item_to_cat_and_index = {} for cat_idx, (cat_str, item_list) in enumerate(categories): for item_idx, item_str in enumerate(item_list): item_to_cat_and_index[(cat_str, item_str)] = (cat_idx, item_idx) Vars = [] for cat_idx, (cat_name, item_list) in enumerate(categories): var = IntVector(cat_name, len(item_list)) Vars.append(var) s = Solver() for cat_idx, (cat_name, item_list) in enumerate(categories): for item_idx, item_str in enumerate(item_list): s.add(Vars[cat_idx][item_idx] >= 1, Vars[cat_idx][item_idx] <= NUM_POSITIONS) s.add(Distinct(Vars[cat_idx])) def pos(cat_str, item_str): (cat_idx, item_idx) = item_to_cat_and_index[(cat_str, item_str)] return Vars[cat_idx][item_idx] # All clues here # The producer whose jam comes from Wild pickings is in the fourth position. s.add(pos("Source", "wild pickings") == 4) # The producer selling Cherry jam is somewhere to the right of the one wearing a Green shirt. s.add(pos("Jam", "cherry") > pos("Shirt", "green")) # Isabella is selling Cherry jam. s.add(pos("Name", "Isabella") == pos("Jam", "cherry")) # The producer wearing a Pink shirt is somewhere between the producer whose jam source is the Backyard and the one selling Watermelon jam, in that order. s.add(And(pos("Source", "backyard") < pos("Shirt", "pink"), pos("Shirt", "pink") < pos("Jam", "watermelon"))) # The producer selling 14 oz jars is somewhere to the right of the one wearing a Green shirt. s.add(pos("Size", "14 oz") > pos("Shirt", "green")) # The producer with 14 oz jars is next to the one selling Raspberry jam. s.add(Abs(pos("Size", "14 oz") - pos("Jam", "raspberry")) == 1) # The Raspberry jam producer is positioned at one of the ends. s.add(Or(pos("Jam", "raspberry") == 1, pos("Jam", "raspberry") == NUM_POSITIONS)) # Barbara is next to the producer whose jam source is the Organic farm. s.add(Abs(pos("Name", "Barbara") - pos("Source", "organic farm")) == 1) # Jane is located somewhere between Nicole and Isabella, in that order. s.add(And(pos("Name", "Nicole") < pos("Name", "Jane"), pos("Name", "Jane") < pos("Name", "Isabella"))) # The producer of Fig jam sources the fruit from an Organic farm. s.add(pos("Jam", "fig") == pos("Source", "organic farm")) # The producer with 10 oz jars is at one of the ends. s.add(Or(pos("Size", "10 oz") == 1, pos("Size", "10 oz") == NUM_POSITIONS)) # The Raspberry jam producer is somewhere to the right of the one wearing a Green shirt. s.add(pos("Jam", "raspberry") > pos("Shirt", "green")) # The producer with 12 oz jars is next to the one who has 6 oz jars. s.add(Abs(pos("Size", "12 oz") - pos("Size", "6 oz")) == 1) # Isabella is next to the producer wearing a Black shirt. s.add(Abs(pos("Name", "Isabella") - pos("Shirt", "black")) == 1) # The producer with 6 oz jars is next to the one whose source is the Local grocer. s.add(Abs(pos("Size", "6 oz") - pos("Source", "local grocer")) == 1) # The producer with 6 oz jars is in the second position. s.add(pos("Size", "6 oz") == 2) # Rachel's source of fruit is the Farmers' coop. s.add(pos("Name", "Rachel") == pos("Source", "farmers' coop")) # Barbara is next to Nicole. s.add(Abs(pos("Name", "Barbara") - pos("Name", "Nicole")) == 1) # The producer wearing an Orange shirt gets her fruit from the Backyard. s.add(pos("Shirt", "orange") == pos("Source", "backyard")) # The producer with 12 oz jars is in the very first position. s.add(pos("Size", "12 oz") == 1) # Solve the puzzle if s.check() == sat: m = s.model() rows = [] header = ["House"] + [cat_name for cat_name, _ in categories] for position in range(1, NUM_POSITIONS + 1): row = [str(position)] for cat_idx, (cat_name, item_list) in enumerate(categories): for item_idx, item_str in enumerate(item_list): if m.evaluate(Vars[cat_idx][item_idx]).as_long() == position: row.append(item_str) break rows.append(row) result_dict = {"header": header, "rows": rows} cnt = 1 block = [] for cat_idx, (cat_name, item_list) in enumerate(categories): for i in range(NUM_POSITIONS): block.append(Vars[cat_idx][i] != m[Vars[cat_idx][i]]) s.add(Or(block)) while s.check() == sat: m = s.model() cnt += 1 block = [] for cat_idx, (cat_name, item_list) in enumerate(categories): for i in range(NUM_POSITIONS): block.append(Vars[cat_idx][i] != m[Vars[cat_idx][i]]) s.add(Or(block)) if cnt == 1: # Output the solution as a JSON string. print(json.dumps(result_dict)) else: print(json.dumps({"error": "Multiple solutions found."})) else: print(json.dumps({"error": "No solution found."})) sys.stdout.flush() # Force immediate output ``` Based on this example, write a similar Z3-based Python code by changing only categories and constraints to represent the puzzle given below.