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Hawk28
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spider-sql-prompts

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train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
soccer_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Player_Attributes ( id, player_fifa_api_id, player_api_id, date, overall_rating, potential, preferred_foot, attacking_work_rate, defensive_work_rate, crossing, finishing, heading_accuracy, short_passing, volleys, dribbling, curve, free_kick_accuracy, long_passing, ball_control, acceleration, sprint_speed, agility, reactions, balance, shot_power, jumping, stamina, strength, long_shots, aggression, interceptions, positioning, vision, penalties, marking, standing_tackle, sliding_tackle, gk_diving, gk_handling, gk_kicking, gk_positioning, gk_reflexes ) # sqlite_sequence ( name, seq ) # Player ( id, player_api_id, player_name, player_fifa_api_id, birthday, height, weight ) # League ( id, country_id, name ) # Country ( id, name ) # Team ( id, team_api_id, team_fifa_api_id, team_long_name, team_short_name ) # Team_Attributes ( id, team_fifa_api_id, team_api_id, date, buildUpPlaySpeed, buildUpPlaySpeedClass, buildUpPlayDribbling, buildUpPlayDribblingClass, buildUpPlayPassing, buildUpPlayPassingClass, buildUpPlayPositioningClass, chanceCreationPassing, chanceCreationPassingClass, chanceCreationCrossing, chanceCreationCrossingClass, chanceCreationShooting, chanceCreationShootingClass, chanceCreationPositioningClass, defencePressure, defencePressureClass, defenceAggression, defenceAggressionClass, defenceTeamWidth, defenceTeamWidthClass, defenceDefenderLineClass ) # # Player_Attributes.player_api_id can be joined with Player.player_api_id # Player_Attributes.player_fifa_api_id can be joined with Player.player_fifa_api_id # League.country_id can be joined with Country.id # Team_Attributes.team_api_id can be joined with Team.team_api_id # Team_Attributes.team_fifa_api_id can be joined with Team.team_fifa_api_id # ### Question: # # List the names of all left-footed players who have overall rating between 85 and 90. # ### SQL: # # SELECT DISTINCT T1.player_name FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id WHERE T2.preferred_foot = "left" AND T2.overall_rating >= 85 AND T2.overall_rating <= 90 # ### End.
soccer_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Player_Attributes ( id, player_fifa_api_id, player_api_id, date, overall_rating, potential, preferred_foot, attacking_work_rate, defensive_work_rate, crossing, finishing, heading_accuracy, short_passing, volleys, dribbling, curve, free_kick_accuracy, long_passing, ball_control, acceleration, sprint_speed, agility, reactions, balance, shot_power, jumping, stamina, strength, long_shots, aggression, interceptions, positioning, vision, penalties, marking, standing_tackle, sliding_tackle, gk_diving, gk_handling, gk_kicking, gk_positioning, gk_reflexes ) # sqlite_sequence ( name, seq ) # Player ( id, player_api_id, player_name, player_fifa_api_id, birthday, height, weight ) # League ( id, country_id, name ) # Country ( id, name ) # Team ( id, team_api_id, team_fifa_api_id, team_long_name, team_short_name ) # Team_Attributes ( id, team_fifa_api_id, team_api_id, date, buildUpPlaySpeed, buildUpPlaySpeedClass, buildUpPlayDribbling, buildUpPlayDribblingClass, buildUpPlayPassing, buildUpPlayPassingClass, buildUpPlayPositioningClass, chanceCreationPassing, chanceCreationPassingClass, chanceCreationCrossing, chanceCreationCrossingClass, chanceCreationShooting, chanceCreationShootingClass, chanceCreationPositioningClass, defencePressure, defencePressureClass, defenceAggression, defenceAggressionClass, defenceTeamWidth, defenceTeamWidthClass, defenceDefenderLineClass ) # # Player_Attributes.player_api_id can be joined with Player.player_api_id # Player_Attributes.player_fifa_api_id can be joined with Player.player_fifa_api_id # League.country_id can be joined with Country.id # Team_Attributes.team_api_id can be joined with Team.team_api_id # Team_Attributes.team_fifa_api_id can be joined with Team.team_fifa_api_id # ### Question: # # What is the average rating for right-footed players and left-footed players? # ### SQL: # # SELECT preferred_foot , avg(overall_rating) FROM Player_Attributes GROUP BY preferred_foot # ### End.
soccer_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Player_Attributes ( id, player_fifa_api_id, player_api_id, date, overall_rating, potential, preferred_foot, attacking_work_rate, defensive_work_rate, crossing, finishing, heading_accuracy, short_passing, volleys, dribbling, curve, free_kick_accuracy, long_passing, ball_control, acceleration, sprint_speed, agility, reactions, balance, shot_power, jumping, stamina, strength, long_shots, aggression, interceptions, positioning, vision, penalties, marking, standing_tackle, sliding_tackle, gk_diving, gk_handling, gk_kicking, gk_positioning, gk_reflexes ) # sqlite_sequence ( name, seq ) # Player ( id, player_api_id, player_name, player_fifa_api_id, birthday, height, weight ) # League ( id, country_id, name ) # Country ( id, name ) # Team ( id, team_api_id, team_fifa_api_id, team_long_name, team_short_name ) # Team_Attributes ( id, team_fifa_api_id, team_api_id, date, buildUpPlaySpeed, buildUpPlaySpeedClass, buildUpPlayDribbling, buildUpPlayDribblingClass, buildUpPlayPassing, buildUpPlayPassingClass, buildUpPlayPositioningClass, chanceCreationPassing, chanceCreationPassingClass, chanceCreationCrossing, chanceCreationCrossingClass, chanceCreationShooting, chanceCreationShootingClass, chanceCreationPositioningClass, defencePressure, defencePressureClass, defenceAggression, defenceAggressionClass, defenceTeamWidth, defenceTeamWidthClass, defenceDefenderLineClass ) # # Player_Attributes.player_api_id can be joined with Player.player_api_id # Player_Attributes.player_fifa_api_id can be joined with Player.player_fifa_api_id # League.country_id can be joined with Country.id # Team_Attributes.team_api_id can be joined with Team.team_api_id # Team_Attributes.team_fifa_api_id can be joined with Team.team_fifa_api_id # ### Question: # # Of all players with an overall rating greater than 80, how many are right-footed and left-footed? # ### SQL: # # SELECT preferred_foot , count(*) FROM Player_Attributes WHERE overall_rating > 80 GROUP BY preferred_foot # ### End.
soccer_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Player_Attributes ( id, player_fifa_api_id, player_api_id, date, overall_rating, potential, preferred_foot, attacking_work_rate, defensive_work_rate, crossing, finishing, heading_accuracy, short_passing, volleys, dribbling, curve, free_kick_accuracy, long_passing, ball_control, acceleration, sprint_speed, agility, reactions, balance, shot_power, jumping, stamina, strength, long_shots, aggression, interceptions, positioning, vision, penalties, marking, standing_tackle, sliding_tackle, gk_diving, gk_handling, gk_kicking, gk_positioning, gk_reflexes ) # sqlite_sequence ( name, seq ) # Player ( id, player_api_id, player_name, player_fifa_api_id, birthday, height, weight ) # League ( id, country_id, name ) # Country ( id, name ) # Team ( id, team_api_id, team_fifa_api_id, team_long_name, team_short_name ) # Team_Attributes ( id, team_fifa_api_id, team_api_id, date, buildUpPlaySpeed, buildUpPlaySpeedClass, buildUpPlayDribbling, buildUpPlayDribblingClass, buildUpPlayPassing, buildUpPlayPassingClass, buildUpPlayPositioningClass, chanceCreationPassing, chanceCreationPassingClass, chanceCreationCrossing, chanceCreationCrossingClass, chanceCreationShooting, chanceCreationShootingClass, chanceCreationPositioningClass, defencePressure, defencePressureClass, defenceAggression, defenceAggressionClass, defenceTeamWidth, defenceTeamWidthClass, defenceDefenderLineClass ) # # Player_Attributes.player_api_id can be joined with Player.player_api_id # Player_Attributes.player_fifa_api_id can be joined with Player.player_fifa_api_id # League.country_id can be joined with Country.id # Team_Attributes.team_api_id can be joined with Team.team_api_id # Team_Attributes.team_fifa_api_id can be joined with Team.team_fifa_api_id # ### Question: # # List all of the player ids with a height of at least 180cm and an overall rating higher than 85. # ### SQL: # # SELECT player_api_id FROM Player WHERE height >= 180 INTERSECT SELECT player_api_id FROM Player_Attributes WHERE overall_rating > 85 # ### End.
soccer_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Player_Attributes ( id, player_fifa_api_id, player_api_id, date, overall_rating, potential, preferred_foot, attacking_work_rate, defensive_work_rate, crossing, finishing, heading_accuracy, short_passing, volleys, dribbling, curve, free_kick_accuracy, long_passing, ball_control, acceleration, sprint_speed, agility, reactions, balance, shot_power, jumping, stamina, strength, long_shots, aggression, interceptions, positioning, vision, penalties, marking, standing_tackle, sliding_tackle, gk_diving, gk_handling, gk_kicking, gk_positioning, gk_reflexes ) # sqlite_sequence ( name, seq ) # Player ( id, player_api_id, player_name, player_fifa_api_id, birthday, height, weight ) # League ( id, country_id, name ) # Country ( id, name ) # Team ( id, team_api_id, team_fifa_api_id, team_long_name, team_short_name ) # Team_Attributes ( id, team_fifa_api_id, team_api_id, date, buildUpPlaySpeed, buildUpPlaySpeedClass, buildUpPlayDribbling, buildUpPlayDribblingClass, buildUpPlayPassing, buildUpPlayPassingClass, buildUpPlayPositioningClass, chanceCreationPassing, chanceCreationPassingClass, chanceCreationCrossing, chanceCreationCrossingClass, chanceCreationShooting, chanceCreationShootingClass, chanceCreationPositioningClass, defencePressure, defencePressureClass, defenceAggression, defenceAggressionClass, defenceTeamWidth, defenceTeamWidthClass, defenceDefenderLineClass ) # # Player_Attributes.player_api_id can be joined with Player.player_api_id # Player_Attributes.player_fifa_api_id can be joined with Player.player_fifa_api_id # League.country_id can be joined with Country.id # Team_Attributes.team_api_id can be joined with Team.team_api_id # Team_Attributes.team_fifa_api_id can be joined with Team.team_fifa_api_id # ### Question: # # List all of the ids for left-footed players with a height between 180cm and 190cm. # ### SQL: # # SELECT player_api_id FROM Player WHERE height >= 180 AND height <= 190 INTERSECT SELECT player_api_id FROM Player_Attributes WHERE preferred_foot = "left" # ### End.
soccer_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Player_Attributes ( id, player_fifa_api_id, player_api_id, date, overall_rating, potential, preferred_foot, attacking_work_rate, defensive_work_rate, crossing, finishing, heading_accuracy, short_passing, volleys, dribbling, curve, free_kick_accuracy, long_passing, ball_control, acceleration, sprint_speed, agility, reactions, balance, shot_power, jumping, stamina, strength, long_shots, aggression, interceptions, positioning, vision, penalties, marking, standing_tackle, sliding_tackle, gk_diving, gk_handling, gk_kicking, gk_positioning, gk_reflexes ) # sqlite_sequence ( name, seq ) # Player ( id, player_api_id, player_name, player_fifa_api_id, birthday, height, weight ) # League ( id, country_id, name ) # Country ( id, name ) # Team ( id, team_api_id, team_fifa_api_id, team_long_name, team_short_name ) # Team_Attributes ( id, team_fifa_api_id, team_api_id, date, buildUpPlaySpeed, buildUpPlaySpeedClass, buildUpPlayDribbling, buildUpPlayDribblingClass, buildUpPlayPassing, buildUpPlayPassingClass, buildUpPlayPositioningClass, chanceCreationPassing, chanceCreationPassingClass, chanceCreationCrossing, chanceCreationCrossingClass, chanceCreationShooting, chanceCreationShootingClass, chanceCreationPositioningClass, defencePressure, defencePressureClass, defenceAggression, defenceAggressionClass, defenceTeamWidth, defenceTeamWidthClass, defenceDefenderLineClass ) # # Player_Attributes.player_api_id can be joined with Player.player_api_id # Player_Attributes.player_fifa_api_id can be joined with Player.player_fifa_api_id # League.country_id can be joined with Country.id # Team_Attributes.team_api_id can be joined with Team.team_api_id # Team_Attributes.team_fifa_api_id can be joined with Team.team_fifa_api_id # ### Question: # # Who are the top 3 players in terms of overall rating? # ### SQL: # # SELECT DISTINCT T1.player_name FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id ORDER BY overall_rating DESC LIMIT 3 # ### End.
soccer_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Player_Attributes ( id, player_fifa_api_id, player_api_id, date, overall_rating, potential, preferred_foot, attacking_work_rate, defensive_work_rate, crossing, finishing, heading_accuracy, short_passing, volleys, dribbling, curve, free_kick_accuracy, long_passing, ball_control, acceleration, sprint_speed, agility, reactions, balance, shot_power, jumping, stamina, strength, long_shots, aggression, interceptions, positioning, vision, penalties, marking, standing_tackle, sliding_tackle, gk_diving, gk_handling, gk_kicking, gk_positioning, gk_reflexes ) # sqlite_sequence ( name, seq ) # Player ( id, player_api_id, player_name, player_fifa_api_id, birthday, height, weight ) # League ( id, country_id, name ) # Country ( id, name ) # Team ( id, team_api_id, team_fifa_api_id, team_long_name, team_short_name ) # Team_Attributes ( id, team_fifa_api_id, team_api_id, date, buildUpPlaySpeed, buildUpPlaySpeedClass, buildUpPlayDribbling, buildUpPlayDribblingClass, buildUpPlayPassing, buildUpPlayPassingClass, buildUpPlayPositioningClass, chanceCreationPassing, chanceCreationPassingClass, chanceCreationCrossing, chanceCreationCrossingClass, chanceCreationShooting, chanceCreationShootingClass, chanceCreationPositioningClass, defencePressure, defencePressureClass, defenceAggression, defenceAggressionClass, defenceTeamWidth, defenceTeamWidthClass, defenceDefenderLineClass ) # # Player_Attributes.player_api_id can be joined with Player.player_api_id # Player_Attributes.player_fifa_api_id can be joined with Player.player_fifa_api_id # League.country_id can be joined with Country.id # Team_Attributes.team_api_id can be joined with Team.team_api_id # Team_Attributes.team_fifa_api_id can be joined with Team.team_fifa_api_id # ### Question: # # List the names and birthdays of the top five players in terms of potential. # ### SQL: # # SELECT DISTINCT T1.player_name , T1.birthday FROM Player AS T1 JOIN Player_Attributes AS T2 ON T1.player_api_id = T2.player_api_id ORDER BY potential DESC LIMIT 5 # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # How many performances are there? # ### SQL: # # SELECT count(*) FROM performance # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # List the hosts of performances in ascending order of attendance. # ### SQL: # # SELECT HOST FROM performance ORDER BY Attendance ASC # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # What are the dates and locations of performances? # ### SQL: # # SELECT Date , LOCATION FROM performance # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the attendances of the performances at location "TD Garden" or "Bell Centre" # ### SQL: # # SELECT Attendance FROM performance WHERE LOCATION = "TD Garden" OR LOCATION = "Bell Centre" # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # What is the average number of attendees for performances? # ### SQL: # # SELECT avg(Attendance) FROM performance # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # What is the date of the performance with the highest number of attendees? # ### SQL: # # SELECT Date FROM performance ORDER BY Attendance DESC LIMIT 1 # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show different locations and the number of performances at each location. # ### SQL: # # SELECT LOCATION , COUNT(*) FROM performance GROUP BY LOCATION # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the most common location of performances. # ### SQL: # # SELECT LOCATION FROM performance GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the locations that have at least two performances. # ### SQL: # # SELECT LOCATION FROM performance GROUP BY LOCATION HAVING COUNT(*) >= 2 # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the locations that have both performances with more than 2000 attendees and performances with less than 1000 attendees. # ### SQL: # # SELECT LOCATION FROM performance WHERE Attendance > 2000 INTERSECT SELECT LOCATION FROM performance WHERE Attendance < 1000 # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the names of members and the location of the performances they attended. # ### SQL: # # SELECT T2.Name , T3.Location FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the names of members and the location of performances they attended in ascending alphabetical order of their names. # ### SQL: # # SELECT T2.Name , T3.Location FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID ORDER BY T2.Name ASC # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the dates of performances with attending members whose roles are "Violin". # ### SQL: # # SELECT T3.Date FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID WHERE T2.Role = "Violin" # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # Show the names of members and the dates of performances they attended in descending order of attendance of the performances. # ### SQL: # # SELECT T2.Name , T3.Date FROM member_attendance AS T1 JOIN member AS T2 ON T1.Member_ID = T2.Member_ID JOIN performance AS T3 ON T1.Performance_ID = T3.Performance_ID ORDER BY T3.Attendance DESC # ### End.
performance_attendance	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # member ( Member_ID, Name, Nationality, Role ) # performance ( Performance_ID, Date, Host, Location, Attendance ) # member_attendance ( Member_ID, Performance_ID, Num_of_Pieces ) # # member_attendance.Performance_ID can be joined with performance.Performance_ID # member_attendance.Member_ID can be joined with member.Member_ID # ### Question: # # List the names of members who did not attend any performance. # ### SQL: # # SELECT Name FROM member WHERE Member_ID NOT IN (SELECT Member_ID FROM member_attendance) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the buildings which have rooms with capacity more than 50. # ### SQL: # # SELECT DISTINCT building FROM classroom WHERE capacity > 50 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the distinct buildings with capacities of greater than 50? # ### SQL: # # SELECT DISTINCT building FROM classroom WHERE capacity > 50 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of rooms that are not in the Lamberton building. # ### SQL: # # SELECT count(*) FROM classroom WHERE building != 'Lamberton' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many classrooms are not in Lamberton? # ### SQL: # # SELECT count(*) FROM classroom WHERE building != 'Lamberton' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the name and building of the departments whose budget is more than the average budget? # ### SQL: # # SELECT dept_name , building FROM department WHERE budget > (SELECT avg(budget) FROM department) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Give the name and building of the departments with greater than average budget. # ### SQL: # # SELECT dept_name , building FROM department WHERE budget > (SELECT avg(budget) FROM department) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the room number of the rooms which can sit 50 to 100 students and their buildings. # ### SQL: # # SELECT building , room_number FROM classroom WHERE capacity BETWEEN 50 AND 100 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the room numbers and corresponding buildings for classrooms which can seat between 50 to 100 students? # ### SQL: # # SELECT building , room_number FROM classroom WHERE capacity BETWEEN 50 AND 100 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name and building of the department with the highest budget. # ### SQL: # # SELECT dept_name , building FROM department ORDER BY budget DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the department name and corresponding building for the department with the greatest budget? # ### SQL: # # SELECT dept_name , building FROM department ORDER BY budget DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the name of the student who has the highest total credits in the History department. # ### SQL: # # SELECT name FROM student WHERE dept_name = 'History' ORDER BY tot_cred DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Give the name of the student in the History department with the most credits. # ### SQL: # # SELECT name FROM student WHERE dept_name = 'History' ORDER BY tot_cred DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many rooms does the Lamberton building have? # ### SQL: # # SELECT count(*) FROM classroom WHERE building = 'Lamberton' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of classrooms in Lamberton. # ### SQL: # # SELECT count(*) FROM classroom WHERE building = 'Lamberton' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many students have advisors? # ### SQL: # # SELECT count(DISTINCT s_id) FROM advisor # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of students who have advisors. # ### SQL: # # SELECT count(DISTINCT s_id) FROM advisor # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many departments offer courses? # ### SQL: # # SELECT count(DISTINCT dept_name) FROM course # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of departments which offer courses. # ### SQL: # # SELECT count(DISTINCT dept_name) FROM course # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many different courses offered by Physics department? # ### SQL: # # SELECT count(DISTINCT course_id) FROM course WHERE dept_name = 'Physics' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of courses in the Physics department. # ### SQL: # # SELECT count(DISTINCT course_id) FROM course WHERE dept_name = 'Physics' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the title of courses that have two prerequisites? # ### SQL: # # SELECT T1.title FROM course AS T1 JOIN prereq AS T2 ON T1.course_id = T2.course_id GROUP BY T2.course_id HAVING count(*) = 2 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the titles for courses with two prerequisites? # ### SQL: # # SELECT T1.title FROM course AS T1 JOIN prereq AS T2 ON T1.course_id = T2.course_id GROUP BY T2.course_id HAVING count(*) = 2 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the title, credit, and department name of courses that have more than one prerequisites? # ### SQL: # # SELECT T1.title , T1.credits , T1.dept_name FROM course AS T1 JOIN prereq AS T2 ON T1.course_id = T2.course_id GROUP BY T2.course_id HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the title, credit value, and department name for courses with more than one prerequisite? # ### SQL: # # SELECT T1.title , T1.credits , T1.dept_name FROM course AS T1 JOIN prereq AS T2 ON T1.course_id = T2.course_id GROUP BY T2.course_id HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many courses that do not have prerequisite? # ### SQL: # # SELECT count(*) FROM course WHERE course_id NOT IN (SELECT course_id FROM prereq) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of courses without prerequisites. # ### SQL: # # SELECT count(*) FROM course WHERE course_id NOT IN (SELECT course_id FROM prereq) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name of the courses that do not have any prerequisite? # ### SQL: # # SELECT title FROM course WHERE course_id NOT IN (SELECT course_id FROM prereq) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the titles of courses without prerequisites? # ### SQL: # # SELECT title FROM course WHERE course_id NOT IN (SELECT course_id FROM prereq) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many different instructors have taught some course? # ### SQL: # # SELECT COUNT (DISTINCT id) FROM teaches # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of distinct instructors who have taught a course. # ### SQL: # # SELECT COUNT (DISTINCT id) FROM teaches # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the total budgets of the Marketing or Finance department. # ### SQL: # # SELECT sum(budget) FROM department WHERE dept_name = 'Marketing' OR dept_name = 'Finance' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the sum of budgets of the Marketing and Finance departments? # ### SQL: # # SELECT sum(budget) FROM department WHERE dept_name = 'Marketing' OR dept_name = 'Finance' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the department name of the instructor whose name contains 'Soisalon'. # ### SQL: # # SELECT dept_name FROM instructor WHERE name LIKE '%Soisalon%' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the name of the department with an instructure who has a name like 'Soisalon'? # ### SQL: # # SELECT dept_name FROM instructor WHERE name LIKE '%Soisalon%' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many rooms whose capacity is less than 50 does the Lamberton building have? # ### SQL: # # SELECT count(*) FROM classroom WHERE building = 'Lamberton' AND capacity < 50 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Count the number of rooms in Lamberton with capacity lower than 50. # ### SQL: # # SELECT count(*) FROM classroom WHERE building = 'Lamberton' AND capacity < 50 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name and budget of departments whose budgets are more than the average budget. # ### SQL: # # SELECT dept_name , budget FROM department WHERE budget > (SELECT avg(budget) FROM department) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the names and budgets of departments with budgets greater than the average? # ### SQL: # # SELECT dept_name , budget FROM department WHERE budget > (SELECT avg(budget) FROM department) # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # what is the name of the instructor who is in Statistics department and earns the lowest salary? # ### SQL: # # SELECT name FROM instructor WHERE dept_name = 'Statistics' ORDER BY salary LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Give the name of the lowest earning instructor in the Statistics department. # ### SQL: # # SELECT name FROM instructor WHERE dept_name = 'Statistics' ORDER BY salary LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the title of course that is provided by both Statistics and Psychology departments. # ### SQL: # # SELECT title FROM course WHERE dept_name = 'Statistics' INTERSECT SELECT title FROM course WHERE dept_name = 'Psychology' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the title of a course that is listed in both the Statistics and Psychology departments? # ### SQL: # # SELECT title FROM course WHERE dept_name = 'Statistics' INTERSECT SELECT title FROM course WHERE dept_name = 'Psychology' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the title of course that is provided by Statistics but not Psychology departments. # ### SQL: # # SELECT title FROM course WHERE dept_name = 'Statistics' EXCEPT SELECT title FROM course WHERE dept_name = 'Psychology' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the titles of courses that are in the Statistics department but not the Psychology department? # ### SQL: # # SELECT title FROM course WHERE dept_name = 'Statistics' EXCEPT SELECT title FROM course WHERE dept_name = 'Psychology' # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the id of instructors who taught a class in Fall 2009 but not in Spring 2010. # ### SQL: # # SELECT id FROM teaches WHERE semester = 'Fall' AND YEAR = 2009 EXCEPT SELECT id FROM teaches WHERE semester = 'Spring' AND YEAR = 2010 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the ids of instructors who taught in the Fall of 2009 but not in the Spring of 2010? # ### SQL: # # SELECT id FROM teaches WHERE semester = 'Fall' AND YEAR = 2009 EXCEPT SELECT id FROM teaches WHERE semester = 'Spring' AND YEAR = 2010 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name of students who took any class in the years of 2009 and 2010. # ### SQL: # # SELECT DISTINCT T1.name FROM student AS T1 JOIN takes AS T2 ON T1.id = T2.id WHERE YEAR = 2009 OR YEAR = 2010 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the names of the students who took classes in 2009 or 2010? # ### SQL: # # SELECT DISTINCT T1.name FROM student AS T1 JOIN takes AS T2 ON T1.id = T2.id WHERE YEAR = 2009 OR YEAR = 2010 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the names of the top 3 departments that provide the largest amount of courses? # ### SQL: # # SELECT dept_name FROM course GROUP BY dept_name ORDER BY count(*) DESC LIMIT 3 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the names of the 3 departments with the most courses? # ### SQL: # # SELECT dept_name FROM course GROUP BY dept_name ORDER BY count(*) DESC LIMIT 3 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name of the department that offers the highest total credits? # ### SQL: # # SELECT dept_name FROM course GROUP BY dept_name ORDER BY sum(credits) DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What is the name of the department with the most credits? # ### SQL: # # SELECT dept_name FROM course GROUP BY dept_name ORDER BY sum(credits) DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # List the names of all courses ordered by their titles and credits. # ### SQL: # # SELECT title FROM course ORDER BY title , credits # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Given the titles of all courses, in order of titles and credits. # ### SQL: # # SELECT title FROM course ORDER BY title , credits # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Which department has the lowest budget? # ### SQL: # # SELECT dept_name FROM department ORDER BY budget LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Give the name of the department with the lowest budget. # ### SQL: # # SELECT dept_name FROM department ORDER BY budget LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # List the names and buildings of all departments sorted by the budget from large to small. # ### SQL: # # SELECT dept_name , building FROM department ORDER BY budget DESC # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the names and buildings of the deparments, sorted by budget descending? # ### SQL: # # SELECT dept_name , building FROM department ORDER BY budget DESC # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Who is the instructor with the highest salary? # ### SQL: # # SELECT name FROM instructor ORDER BY salary DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Give the name of the highest paid instructor. # ### SQL: # # SELECT name FROM instructor ORDER BY salary DESC LIMIT 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # List the information of all instructors ordered by their salary in ascending order. # ### SQL: # # SELECT * FROM instructor ORDER BY salary # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Give all information regarding instructors, in order of salary from least to greatest. # ### SQL: # # SELECT * FROM instructor ORDER BY salary # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name of the students and their department names sorted by their total credits in ascending order. # ### SQL: # # SELECT name , dept_name FROM student ORDER BY tot_cred # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the names of students and their respective departments, ordered by number of credits from least to greatest? # ### SQL: # # SELECT name , dept_name FROM student ORDER BY tot_cred # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # list in alphabetic order all course names and their instructors' names in year 2008. # ### SQL: # # SELECT T1.title , T3.name FROM course AS T1 JOIN teaches AS T2 ON T1.course_id = T2.course_id JOIN instructor AS T3 ON T2.id = T3.id WHERE YEAR = 2008 ORDER BY T1.title # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Show all titles and their instructors' names for courses in 2008, in alphabetical order by title. # ### SQL: # # SELECT T1.title , T3.name FROM course AS T1 JOIN teaches AS T2 ON T1.course_id = T2.course_id JOIN instructor AS T3 ON T2.id = T3.id WHERE YEAR = 2008 ORDER BY T1.title # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name of instructors who are advising more than one student. # ### SQL: # # SELECT T1.name FROM instructor AS T1 JOIN advisor AS T2 ON T1.id = T2.i_id GROUP BY T2.i_id HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the names of instructors who advise more than one student? # ### SQL: # # SELECT T1.name FROM instructor AS T1 JOIN advisor AS T2 ON T1.id = T2.i_id GROUP BY T2.i_id HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the name of the students who have more than one advisor? # ### SQL: # # SELECT T1.name FROM student AS T1 JOIN advisor AS T2 ON T1.id = T2.s_id GROUP BY T2.s_id HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the names of students who have more than one advisor? # ### SQL: # # SELECT T1.name FROM student AS T1 JOIN advisor AS T2 ON T1.id = T2.s_id GROUP BY T2.s_id HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the number of rooms with more than 50 capacity for each building. # ### SQL: # # SELECT count(*) , building FROM classroom WHERE capacity > 50 GROUP BY building # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many rooms in each building have a capacity of over 50? # ### SQL: # # SELECT count(*) , building FROM classroom WHERE capacity > 50 GROUP BY building # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the maximum and average capacity among rooms in each building. # ### SQL: # # SELECT max(capacity) , avg(capacity) , building FROM classroom GROUP BY building # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the greatest and average capacity for rooms in each building? # ### SQL: # # SELECT max(capacity) , avg(capacity) , building FROM classroom GROUP BY building # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the title of the course that is offered by more than one department. # ### SQL: # # SELECT title FROM course GROUP BY title HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # What are the titles of courses that are offered in more than one department? # ### SQL: # # SELECT title FROM course GROUP BY title HAVING count(*) > 1 # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # Find the total credits of courses provided by different department. # ### SQL: # # SELECT sum(credits) , dept_name FROM course GROUP BY dept_name # ### End.
college_2	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # classroom ( building, room_number, capacity ) # department ( dept_name, building, budget ) # course ( course_id, title, dept_name, credits ) # instructor ( ID, name, dept_name, salary ) # section ( course_id, sec_id, semester, year, building, room_number, time_slot_id ) # teaches ( ID, course_id, sec_id, semester, year ) # student ( ID, name, dept_name, tot_cred ) # takes ( ID, course_id, sec_id, semester, year, grade ) # advisor ( s_ID, i_ID ) # time_slot ( time_slot_id, day, start_hr, start_min, end_hr, end_min ) # prereq ( course_id, prereq_id ) # # course.dept_name can be joined with department.dept_name # instructor.dept_name can be joined with department.dept_name # section.building can be joined with classroom.building # section.room_number can be joined with classroom.room_number # section.course_id can be joined with course.course_id # teaches.ID can be joined with instructor.ID # teaches.course_id can be joined with section.course_id # teaches.sec_id can be joined with section.sec_id # teaches.semester can be joined with section.semester # teaches.year can be joined with section.year # student.dept_name can be joined with department.dept_name # takes.ID can be joined with student.ID # takes.course_id can be joined with section.course_id # takes.sec_id can be joined with section.sec_id # takes.semester can be joined with section.semester # takes.year can be joined with section.year # advisor.s_ID can be joined with student.ID # advisor.i_ID can be joined with instructor.ID # prereq.prereq_id can be joined with course.course_id # prereq.course_id can be joined with course.course_id # ### Question: # # How many total credits are offered by each department? # ### SQL: # # SELECT sum(credits) , dept_name FROM course GROUP BY dept_name # ### End.

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