Datasets:
HusnaManakkot
/
haispider

Dataset card Data Studio Files
xet
Community
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question_toks
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manufacturer
SELECT t1.manufacturer_id , t1.num_of_shops FROM manufacturer AS t1 JOIN furniture_manufacte AS t2 ON t1.manufacturer_id = t2.manufacturer_id ORDER BY t2.Price_in_Dollar DESC LIMIT 1
Find the id and number of shops for the company that produces the most expensive furniture.
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[ "Find", "the", "id", "and", "number", "of", "shops", "for", "the", "company", "that", "produces", "the", "most", "expensive", "furniture", "." ]
manufacturer
SELECT count(*) , t1.name FROM manufacturer AS t1 JOIN furniture_manufacte AS t2 ON t1.manufacturer_id = t2.manufacturer_id GROUP BY t1.manufacturer_id
Find the number of funiture types produced by each manufacturer as well as the company names.
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[ "select", "count", "(", "*", ")", ",", "t1", ".", "name", "from", "manufacturer", "as", "t1", "join", "furniture_manufacte", "as", "t2", "on", "t1", ".", "manufacturer_id", "=", "t2", ".", "manufacturer_id", "group", "by", "t1", ".", "manufacturer_id" ]
[ "Find", "the", "number", "of", "funiture", "types", "produced", "by", "each", "manufacturer", "as", "well", "as", "the", "company", "names", "." ]
manufacturer
SELECT t1.name , t2.price_in_dollar FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID
Give me the names and prices of furnitures which some companies are manufacturing.
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[ "Give", "me", "the", "names", "and", "prices", "of", "furnitures", "which", "some", "companies", "are", "manufacturing", "." ]
manufacturer
SELECT Market_Rate , name FROM furniture WHERE Furniture_ID NOT IN (SELECT Furniture_ID FROM furniture_manufacte)
Find the market shares and names of furnitures which no any company is producing in our records.
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[ "Find", "the", "market", "shares", "and", "names", "of", "furnitures", "which", "no", "any", "company", "is", "producing", "in", "our", "records", "." ]
manufacturer
SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id = t3.manufacturer_id WHERE t1.num_of_component < 6 INTERSECT SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id = t3.manufacturer_id WHERE t1.num_of_component > 10
Find the name of the company that produces both furnitures with less than 6 components and furnitures with more than 10 components.
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hr_1
SELECT T1.first_name , T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
Display the first name and department name for each employee.
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[ "Display", "the", "first", "name", "and", "department", "name", "for", "each", "employee", "." ]
hr_1
SELECT T1.first_name , T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
What are the first name and department name of all employees?
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hr_1
SELECT first_name , last_name , salary FROM employees WHERE salary < 6000
List the full name (first and last name), and salary for those employees who earn below 6000.
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hr_1
SELECT first_name , last_name , salary FROM employees WHERE salary < 6000
What are the full names and salaries for any employees earning less than 6000?
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hr_1
SELECT first_name , department_id FROM employees WHERE last_name = 'McEwen'
Display the first name, and department number for all employees whose last name is "McEwen".
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hr_1
SELECT first_name , department_id FROM employees WHERE last_name = 'McEwen'
What are the first names and department numbers for employees with last name McEwen?
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[ "What", "are", "the", "first", "names", "and", "department", "numbers", "for", "employees", "with", "last", "name", "McEwen", "?" ]
hr_1
SELECT * FROM employees WHERE department_id = "null"
Return all the information for all employees without any department number.
[ "SELECT", "*", "FROM", "employees", "WHERE", "department_id", "=", "``", "null", "''" ]
[ "select", "*", "from", "employees", "where", "department_id", "=", "value" ]
[ "Return", "all", "the", "information", "for", "all", "employees", "without", "any", "department", "number", "." ]
hr_1
SELECT * FROM employees WHERE department_id = "null"
What are all the employees without a department number?
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[ "select", "*", "from", "employees", "where", "department_id", "=", "value" ]
[ "What", "are", "all", "the", "employees", "without", "a", "department", "number", "?" ]
hr_1
SELECT * FROM departments WHERE department_name = 'Marketing'
Display all the information about the department Marketing.
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[ "select", "*", "from", "departments", "where", "department_name", "=", "value" ]
[ "Display", "all", "the", "information", "about", "the", "department", "Marketing", "." ]
hr_1
SELECT * FROM departments WHERE department_name = 'Marketing'
What is all the information about the Marketing department?
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[ "What", "is", "all", "the", "information", "about", "the", "Marketing", "department", "?" ]
hr_1
SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%'
when is the hire date for those employees whose first name does not containing the letter M?
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[ "select", "hire_date", "from", "employees", "where", "first_name", "not", "like", "value" ]
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hr_1
SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%'
On what dates were employees without the letter M in their first names hired?
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hr_1
SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%'
display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M.
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hr_1
SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%'
What are the full name, hire date, salary, and department id for employees without the letter M in their first name?
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hr_1
SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M and make the result set in ascending order by department number.
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[ "select", "first_name", ",", "last_name", ",", "hire_date", ",", "salary", ",", "department_id", "from", "employees", "where", "first_name", "not", "like", "value", "order", "by", "department_id" ]
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hr_1
SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
What are the full name, hire data, salary and department id for employees without the letter M in their first name, ordered by ascending department id?
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hr_1
SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
what is the phone number of employees whose salary is in the range of 8000 and 12000?
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hr_1
SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
Return the phone numbers of employees with salaries between 8000 and 12000.
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[ "Return", "the", "phone", "numbers", "of", "employees", "with", "salaries", "between", "8000", "and", "12000", "." ]
hr_1
SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR department_id != 40
display all the information of employees whose salary is in the range of 8000 and 12000 and commission is not null or department number does not equal to 40.
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hr_1
SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR department_id != 40
Return all information about employees with salaries between 8000 and 12000 for which commission is not null or where their department id is not 40.
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hr_1
SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null"
What are the full name (first and last name) and salary for all employees who does not have any value for commission?
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hr_1
SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null"
Return the full names and salaries of employees with null commissions.
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[ "Return", "the", "full", "names", "and", "salaries", "of", "employees", "with", "null", "commissions", "." ]
hr_1
SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m'
Display the first and last name, and salary for those employees whose first name is ending with the letter m.
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hr_1
SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m'
Return the full names and salaries for employees with first names that end with the letter m.
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hr_1
SELECT job_id , hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
Find job id and date of hire for those employees who was hired between November 5th, 2007 and July 5th, 2009.
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hr_1
SELECT job_id , hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
What are the job ids and dates of hire for employees hired after November 5th, 2007 and before July 5th, 2009?
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hr_1
SELECT first_name , last_name FROM employees WHERE department_id = 70 OR department_id = 90
What are the first and last name for those employees who works either in department 70 or 90?
[ "SELECT", "first_name", ",", "last_name", "FROM", "employees", "WHERE", "department_id", "=", "70", "OR", "department_id", "=", "90" ]
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[ "What", "are", "the", "first", "and", "last", "name", "for", "those", "employees", "who", "works", "either", "in", "department", "70", "or", "90", "?" ]
hr_1
SELECT first_name , last_name FROM employees WHERE department_id = 70 OR department_id = 90
What are the full names of employees who with in department 70 or 90?
[ "SELECT", "first_name", ",", "last_name", "FROM", "employees", "WHERE", "department_id", "=", "70", "OR", "department_id", "=", "90" ]
[ "select", "first_name", ",", "last_name", "from", "employees", "where", "department_id", "=", "value", "or", "department_id", "=", "value" ]
[ "What", "are", "the", "full", "names", "of", "employees", "who", "with", "in", "department", "70", "or", "90", "?" ]
hr_1
SELECT salary , manager_id FROM employees WHERE manager_id != "null"
Find the salary and manager number for those employees who is working under a manager.
[ "SELECT", "salary", ",", "manager_id", "FROM", "employees", "WHERE", "manager_id", "!", "=", "``", "null", "''" ]
[ "select", "salary", ",", "manager_id", "from", "employees", "where", "manager_id", "!", "=", "value" ]
[ "Find", "the", "salary", "and", "manager", "number", "for", "those", "employees", "who", "is", "working", "under", "a", "manager", "." ]
hr_1
SELECT salary , manager_id FROM employees WHERE manager_id != "null"
What are the salaries and manager ids for employees who have managers?
[ "SELECT", "salary", ",", "manager_id", "FROM", "employees", "WHERE", "manager_id", "!", "=", "``", "null", "''" ]
[ "select", "salary", ",", "manager_id", "from", "employees", "where", "manager_id", "!", "=", "value" ]
[ "What", "are", "the", "salaries", "and", "manager", "ids", "for", "employees", "who", "have", "managers", "?" ]
hr_1
SELECT * FROM employees WHERE hire_date < '2002-06-21'
display all the details from Employees table for those employees who was hired before 2002-06-21.
[ "SELECT", "*", "FROM", "employees", "WHERE", "hire_date", "<", "'2002-06-21", "'" ]
[ "select", "*", "from", "employees", "where", "hire_date", "<", "value" ]
[ "display", "all", "the", "details", "from", "Employees", "table", "for", "those", "employees", "who", "was", "hired", "before", "2002-06-21", "." ]
hr_1
SELECT * FROM employees WHERE hire_date < '2002-06-21'
What is all the information about employees hired before June 21, 2002?
[ "SELECT", "*", "FROM", "employees", "WHERE", "hire_date", "<", "'2002-06-21", "'" ]
[ "select", "*", "from", "employees", "where", "hire_date", "<", "value" ]
[ "What", "is", "all", "the", "information", "about", "employees", "hired", "before", "June", "21", ",", "2002", "?" ]
hr_1
SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC
display all the information for all employees who have the letters D or S in their first name and also arrange the result in descending order by salary.
[ "SELECT", "*", "FROM", "employees", "WHERE", "first_name", "LIKE", "'", "%", "D", "%", "'", "OR", "first_name", "LIKE", "'", "%", "S", "%", "'", "ORDER", "BY", "salary", "DESC" ]
[ "select", "*", "from", "employees", "where", "first_name", "like", "value", "or", "first_name", "like", "value", "order", "by", "salary", "desc" ]
[ "display", "all", "the", "information", "for", "all", "employees", "who", "have", "the", "letters", "D", "or", "S", "in", "their", "first", "name", "and", "also", "arrange", "the", "result", "in", "descending", "order", "by", "salary", "." ]
hr_1
SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC
What is all the information about employees with D or S in their first name, ordered by salary descending?
[ "SELECT", "*", "FROM", "employees", "WHERE", "first_name", "LIKE", "'", "%", "D", "%", "'", "OR", "first_name", "LIKE", "'", "%", "S", "%", "'", "ORDER", "BY", "salary", "DESC" ]
[ "select", "*", "from", "employees", "where", "first_name", "like", "value", "or", "first_name", "like", "value", "order", "by", "salary", "desc" ]
[ "What", "is", "all", "the", "information", "about", "employees", "with", "D", "or", "S", "in", "their", "first", "name", ",", "ordered", "by", "salary", "descending", "?" ]
hr_1
SELECT * FROM employees WHERE hire_date > '1987-09-07'
display those employees who joined after 7th September, 1987.
[ "SELECT", "*", "FROM", "employees", "WHERE", "hire_date", ">", "'1987-09-07", "'" ]
[ "select", "*", "from", "employees", "where", "hire_date", ">", "value" ]
[ "display", "those", "employees", "who", "joined", "after", "7th", "September", ",", "1987", "." ]
hr_1
SELECT * FROM employees WHERE hire_date > '1987-09-07'
Which employees were hired after September 7th, 1987?
[ "SELECT", "*", "FROM", "employees", "WHERE", "hire_date", ">", "'1987-09-07", "'" ]
[ "select", "*", "from", "employees", "where", "hire_date", ">", "value" ]
[ "Which", "employees", "were", "hired", "after", "September", "7th", ",", "1987", "?" ]
hr_1
SELECT job_title FROM jobs WHERE min_salary > 9000
display the job title of jobs which minimum salary is greater than 9000.
[ "SELECT", "job_title", "FROM", "jobs", "WHERE", "min_salary", ">", "9000" ]
[ "select", "job_title", "from", "jobs", "where", "min_salary", ">", "value" ]
[ "display", "the", "job", "title", "of", "jobs", "which", "minimum", "salary", "is", "greater", "than", "9000", "." ]
hr_1
SELECT job_title FROM jobs WHERE min_salary > 9000
Which job titles correspond to jobs with salaries over 9000?
[ "SELECT", "job_title", "FROM", "jobs", "WHERE", "min_salary", ">", "9000" ]
[ "select", "job_title", "from", "jobs", "where", "min_salary", ">", "value" ]
[ "Which", "job", "titles", "correspond", "to", "jobs", "with", "salaries", "over", "9000", "?" ]
hr_1
SELECT job_title , max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
display job Title, the difference between minimum and maximum salaries for those jobs which max salary within the range 12000 to 18000.
[ "SELECT", "job_title", ",", "max_salary", "-", "min_salary", "FROM", "jobs", "WHERE", "max_salary", "BETWEEN", "12000", "AND", "18000" ]
[ "select", "job_title", ",", "max_salary", "-", "min_salary", "from", "jobs", "where", "max_salary", "between", "value", "and", "value" ]
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hr_1
SELECT job_title , max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
What are the job titles, and range of salaries for jobs with maximum salary between 12000 and 18000?
[ "SELECT", "job_title", ",", "max_salary", "-", "min_salary", "FROM", "jobs", "WHERE", "max_salary", "BETWEEN", "12000", "AND", "18000" ]
[ "select", "job_title", ",", "max_salary", "-", "min_salary", "from", "jobs", "where", "max_salary", "between", "value", "and", "value" ]
[ "What", "are", "the", "job", "titles", ",", "and", "range", "of", "salaries", "for", "jobs", "with", "maximum", "salary", "between", "12000", "and", "18000", "?" ]
hr_1
SELECT email FROM employees WHERE commission_pct = "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
display the emails of the employees who have no commission percentage and salary within the range 7000 to 12000 and works in that department which number is 50.
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[ "select", "email", "from", "employees", "where", "commission_pct", "=", "value", "and", "salary", "between", "value", "and", "value", "and", "department_id", "=", "value" ]
[ "display", "the", "emails", "of", "the", "employees", "who", "have", "no", "commission", "percentage", "and", "salary", "within", "the", "range", "7000", "to", "12000", "and", "works", "in", "that", "department", "which", "number", "is", "50", "." ]
hr_1
SELECT email FROM employees WHERE commission_pct = "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
What are the emails of employees with null commission, salary between 7000 and 12000, and who work in department 50?
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[ "select", "email", "from", "employees", "where", "commission_pct", "=", "value", "and", "salary", "between", "value", "and", "value", "and", "department_id", "=", "value" ]
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hr_1
SELECT employee_id , MAX(end_date) FROM job_history GROUP BY employee_id
display the employee ID for each employee and the date on which he ended his previous job.
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[ "select", "employee_id", ",", "max", "(", "end_date", ")", "from", "job_history", "group", "by", "employee_id" ]
[ "display", "the", "employee", "ID", "for", "each", "employee", "and", "the", "date", "on", "which", "he", "ended", "his", "previous", "job", "." ]
hr_1
SELECT employee_id , MAX(end_date) FROM job_history GROUP BY employee_id
What are the employee ids for each employee and final dates of employment at their last job?
[ "SELECT", "employee_id", ",", "MAX", "(", "end_date", ")", "FROM", "job_history", "GROUP", "BY", "employee_id" ]
[ "select", "employee_id", ",", "max", "(", "end_date", ")", "from", "job_history", "group", "by", "employee_id" ]
[ "What", "are", "the", "employee", "ids", "for", "each", "employee", "and", "final", "dates", "of", "employment", "at", "their", "last", "job", "?" ]
hr_1
SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
display those departments where more than ten employees work who got a commission percentage.
[ "SELECT", "department_id", "FROM", "employees", "GROUP", "BY", "department_id", "HAVING", "COUNT", "(", "commission_pct", ")", ">", "10" ]
[ "select", "department_id", "from", "employees", "group", "by", "department_id", "having", "count", "(", "commission_pct", ")", ">", "value" ]
[ "display", "those", "departments", "where", "more", "than", "ten", "employees", "work", "who", "got", "a", "commission", "percentage", "." ]
hr_1
SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
What are the department ids for which more than 10 employees had a commission?
[ "SELECT", "department_id", "FROM", "employees", "GROUP", "BY", "department_id", "HAVING", "COUNT", "(", "commission_pct", ")", ">", "10" ]
[ "select", "department_id", "from", "employees", "group", "by", "department_id", "having", "count", "(", "commission_pct", ")", ">", "value" ]
[ "What", "are", "the", "department", "ids", "for", "which", "more", "than", "10", "employees", "had", "a", "commission", "?" ]
hr_1
SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
Find the ids of the departments where any manager is managing 4 or more employees.
[ "SELECT", "DISTINCT", "department_id", "FROM", "employees", "GROUP", "BY", "department_id", ",", "manager_id", "HAVING", "COUNT", "(", "employee_id", ")", ">", "=", "4" ]
[ "select", "distinct", "department_id", "from", "employees", "group", "by", "department_id", ",", "manager_id", "having", "count", "(", "employee_id", ")", ">", "=", "value" ]
[ "Find", "the", "ids", "of", "the", "departments", "where", "any", "manager", "is", "managing", "4", "or", "more", "employees", "." ]
hr_1
SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
What are department ids for departments with managers managing more than 3 employees?
[ "SELECT", "DISTINCT", "department_id", "FROM", "employees", "GROUP", "BY", "department_id", ",", "manager_id", "HAVING", "COUNT", "(", "employee_id", ")", ">", "=", "4" ]
[ "select", "distinct", "department_id", "from", "employees", "group", "by", "department_id", ",", "manager_id", "having", "count", "(", "employee_id", ")", ">", "=", "value" ]
[ "What", "are", "department", "ids", "for", "departments", "with", "managers", "managing", "more", "than", "3", "employees", "?" ]
hr_1
SELECT department_id , AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id
display the average salary of employees for each department who gets a commission percentage.
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[ "select", "department_id", ",", "avg", "(", "salary", ")", "from", "employees", "where", "commission_pct", "!", "=", "value", "group", "by", "department_id" ]
[ "display", "the", "average", "salary", "of", "employees", "for", "each", "department", "who", "gets", "a", "commission", "percentage", "." ]
hr_1
SELECT department_id , AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id
What is the average salary of employees who have a commission percentage that is not null?
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[ "select", "department_id", ",", "avg", "(", "salary", ")", "from", "employees", "where", "commission_pct", "!", "=", "value", "group", "by", "department_id" ]
[ "What", "is", "the", "average", "salary", "of", "employees", "who", "have", "a", "commission", "percentage", "that", "is", "not", "null", "?" ]
hr_1
SELECT country_id , COUNT(*) FROM locations GROUP BY country_id
display the country ID and number of cities for each country.
[ "SELECT", "country_id", ",", "COUNT", "(", "*", ")", "FROM", "locations", "GROUP", "BY", "country_id" ]
[ "select", "country_id", ",", "count", "(", "*", ")", "from", "locations", "group", "by", "country_id" ]
[ "display", "the", "country", "ID", "and", "number", "of", "cities", "for", "each", "country", "." ]
hr_1
SELECT country_id , COUNT(*) FROM locations GROUP BY country_id
Give the country id and corresponding count of cities in each country.
[ "SELECT", "country_id", ",", "COUNT", "(", "*", ")", "FROM", "locations", "GROUP", "BY", "country_id" ]
[ "select", "country_id", ",", "count", "(", "*", ")", "from", "locations", "group", "by", "country_id" ]
[ "Give", "the", "country", "id", "and", "corresponding", "count", "of", "cities", "in", "each", "country", "." ]
hr_1
SELECT job_id FROM job_history WHERE end_date - start_date > 300 GROUP BY job_id HAVING COUNT(*) >= 2
display job ID for those jobs that were done by two or more for more than 300 days.
[ "SELECT", "job_id", "FROM", "job_history", "WHERE", "end_date", "-", "start_date", ">", "300", "GROUP", "BY", "job_id", "HAVING", "COUNT", "(", "*", ")", ">", "=", "2" ]
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[ "display", "job", "ID", "for", "those", "jobs", "that", "were", "done", "by", "two", "or", "more", "for", "more", "than", "300", "days", "." ]
hr_1
SELECT job_id FROM job_history WHERE end_date - start_date > 300 GROUP BY job_id HAVING COUNT(*) >= 2
What are the job ids for jobs done more than once for a period of more than 300 days?
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[ "What", "are", "the", "job", "ids", "for", "jobs", "done", "more", "than", "once", "for", "a", "period", "of", "more", "than", "300", "days", "?" ]
hr_1
SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2
display the ID for those employees who did two or more jobs in the past.
[ "SELECT", "employee_id", "FROM", "job_history", "GROUP", "BY", "employee_id", "HAVING", "COUNT", "(", "*", ")", ">", "=", "2" ]
[ "select", "employee_id", "from", "job_history", "group", "by", "employee_id", "having", "count", "(", "*", ")", ">", "=", "value" ]
[ "display", "the", "ID", "for", "those", "employees", "who", "did", "two", "or", "more", "jobs", "in", "the", "past", "." ]
hr_1
SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2
What are the employee ids for employees who have held two or more jobs?
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[ "What", "are", "the", "employee", "ids", "for", "employees", "who", "have", "held", "two", "or", "more", "jobs", "?" ]
hr_1
SELECT T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id
Find employee with ID and name of the country presently where (s)he is working.
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[ "Find", "employee", "with", "ID", "and", "name", "of", "the", "country", "presently", "where", "(", "s", ")", "he", "is", "working", "." ]
hr_1
SELECT T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id
What are all the employee ids and the names of the countries in which they work?
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[ "What", "are", "all", "the", "employee", "ids", "and", "the", "names", "of", "the", "countries", "in", "which", "they", "work", "?" ]
hr_1
SELECT T2.department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY T2.department_name
display the department name and number of employees in each of the department.
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[ "display", "the", "department", "name", "and", "number", "of", "employees", "in", "each", "of", "the", "department", "." ]
hr_1
SELECT T2.department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY T2.department_name
Give the name of each department and the number of employees in each.
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[ "Give", "the", "name", "of", "each", "department", "and", "the", "number", "of", "employees", "in", "each", "." ]
hr_1
SELECT * FROM job_history AS T1 JOIN employees AS T2 ON T1.employee_id = T2.employee_id WHERE T2.salary >= 12000
Can you return all detailed info of jobs which was done by any of the employees who is presently earning a salary on and above 12000?
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hr_1
SELECT * FROM job_history AS T1 JOIN employees AS T2 ON T1.employee_id = T2.employee_id WHERE T2.salary >= 12000
What is all the job history info done by employees earning a salary greater than or equal to 12000?
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hr_1
SELECT job_title , AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id GROUP BY T2.job_title
display job title and average salary of employees.
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[ "display", "job", "title", "and", "average", "salary", "of", "employees", "." ]
hr_1
SELECT job_title , AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id GROUP BY T2.job_title
What is the average salary for each job title?
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[ "What", "is", "the", "average", "salary", "for", "each", "job", "title", "?" ]
hr_1
SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 )
What is the full name ( first name and last name ) for those employees who gets more salary than the employee whose id is 163?
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hr_1
SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 )
Provide the full names of employees earning more than the employee with id 163.
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[ "Provide", "the", "full", "names", "of", "employees", "earning", "more", "than", "the", "employee", "with", "id", "163", "." ]
hr_1
SELECT MIN(salary) , department_id FROM employees GROUP BY department_id
return the smallest salary for every departments.
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[ "return", "the", "smallest", "salary", "for", "every", "departments", "." ]
hr_1
SELECT MIN(salary) , department_id FROM employees GROUP BY department_id
What is the minimum salary in each department?
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hr_1
SELECT first_name , last_name , department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
Find the first name and last name and department id for those employees who earn such amount of salary which is the smallest salary of any of the departments.
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hr_1
SELECT first_name , last_name , department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
What are the full names and department ids for the lowest paid employees across all departments.
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hr_1
SELECT employee_id FROM employees WHERE salary > (SELECT AVG(salary) FROM employees)
Find the employee id for all employees who earn more than the average salary.
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hr_1
SELECT employee_id FROM employees WHERE salary > (SELECT AVG(salary) FROM employees)
What are the employee ids for employees who make more than the average?
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hr_1
SELECT employee_id , salary FROM employees WHERE manager_id = (SELECT employee_id FROM employees WHERE first_name = 'Payam' )
display the employee id and salary of all employees who report to Payam (first name).
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hr_1
SELECT employee_id , salary FROM employees WHERE manager_id = (SELECT employee_id FROM employees WHERE first_name = 'Payam' )
What are the employee ids of employees who report to Payam, and what are their salaries?
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hr_1
SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
find the name of all departments that do actually have one or more employees assigned to them.
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hr_1
SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
What are the names of departments that have at least one employee.
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[ "What", "are", "the", "names", "of", "departments", "that", "have", "at", "least", "one", "employee", "." ]
hr_1
SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T1.employee_id = T2.manager_id
get the details of employees who manage a department.
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[ "get", "the", "details", "of", "employees", "who", "manage", "a", "department", "." ]
hr_1
SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T1.employee_id = T2.manager_id
What is all the information regarding employees who are managers?
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[ "What", "is", "all", "the", "information", "regarding", "employees", "who", "are", "managers", "?" ]
hr_1
SELECT * FROM departments WHERE department_name = 'Marketing'
display all the information about the department Marketing.
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hr_1
SELECT * FROM departments WHERE department_name = 'Marketing'
What is all the information about the Marketing department?
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[ "What", "is", "all", "the", "information", "about", "the", "Marketing", "department", "?" ]
hr_1
SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2
display the ID for those employees who did two or more jobs in the past.
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hr_1
SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2
What are the employee ids for those who had two or more jobs.
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[ "What", "are", "the", "employee", "ids", "for", "those", "who", "had", "two", "or", "more", "jobs", "." ]
hr_1
SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
What are the unique ids of those departments where any manager is managing 4 or more employees.
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hr_1
SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
Give the distinct department ids of departments in which a manager is in charge of 4 or more employees?
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hr_1
SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
Find the job ID for those jobs which average salary is above 8000.
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hr_1
SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
What are the job ids corresponding to jobs with average salary above 8000?
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hr_1
SELECT T1.employee_id , T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id WHERE T1.department_id = 80
display the employee ID and job name for all those jobs in department 80.
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hr_1
SELECT T1.employee_id , T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id WHERE T1.department_id = 80
what are the employee ids and job titles for employees in department 80?
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hr_1
SELECT T1.first_name , T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = 'Finance'
What is the first name and job id for all employees in the Finance department?
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hr_1
SELECT T1.first_name , T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = 'Finance'
Give the first name and job id for all employees in the Finance department.
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hr_1
SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
display all the information of the employees whose salary if within the range of smallest salary and 2500.
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hr_1
SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
What is all the information regarding employees with salaries above the minimum and under 2500?
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hr_1
SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
Find the ids of the employees who does not work in those departments where some employees works whose manager id within the range 100 and 200.
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hr_1
SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
What are the ids for employees who do not work in departments with managers that have ids between 100 and 200?
[ "SELECT", "*", "FROM", "employees", "WHERE", "department_id", "NOT", "IN", "(", "SELECT", "department_id", "FROM", "departments", "WHERE", "manager_id", "BETWEEN", "100", "AND", "200", ")" ]
[ "select", "*", "from", "employees", "where", "department_id", "not", "in", "(", "select", "department_id", "from", "departments", "where", "manager_id", "between", "value", "and", "value", ")" ]
[ "What", "are", "the", "ids", "for", "employees", "who", "do", "not", "work", "in", "departments", "with", "managers", "that", "have", "ids", "between", "100", "and", "200", "?" ]
hr_1
SELECT first_name , last_name , hire_date FROM employees WHERE department_id = (SELECT department_id FROM employees WHERE first_name = "Clara")
display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara.
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[ "select", "first_name", ",", "last_name", ",", "hire_date", "from", "employees", "where", "department_id", "=", "(", "select", "department_id", "from", "employees", "where", "first_name", "=", "value", ")" ]
[ "display", "the", "employee", "name", "(", "first", "name", "and", "last", "name", ")", "and", "hire", "date", "for", "all", "employees", "in", "the", "same", "department", "as", "Clara", "." ]