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CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many females does this network has?
|
SELECT count(*) FROM Person WHERE gender = 'female'
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many females are in the network?
|
SELECT count(*) FROM Person WHERE gender = 'female'
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the average age for all person?
|
SELECT avg(age) FROM Person
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the average age for all people in the table?
|
SELECT avg(age) FROM Person
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many different cities are they from?
|
SELECT count(DISTINCT city) FROM Person
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many different cities do people originate from?
|
SELECT count(DISTINCT city) FROM Person
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many type of jobs do they have?
|
SELECT count(DISTINCT job) FROM Person
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many different jobs are listed?
|
SELECT count(DISTINCT job) FROM Person
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who is the oldest person?
|
SELECT name FROM Person WHERE age = (SELECT max(age) FROM person)
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the name of the person who is the oldest?
|
SELECT name FROM Person WHERE age = (SELECT max(age) FROM person)
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who is the oldest person whose job is student?
|
SELECT name FROM Person WHERE job = 'student' AND age = (SELECT max(age) FROM person WHERE job = 'student' )
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the name of the oldest student?
|
SELECT name FROM Person WHERE job = 'student' AND age = (SELECT max(age) FROM person WHERE job = 'student' )
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who is the youngest male?
|
SELECT name FROM Person WHERE gender = 'male' AND age = (SELECT min(age) FROM person WHERE gender = 'male' )
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the name of the youngest male?
|
SELECT name FROM Person WHERE gender = 'male' AND age = (SELECT min(age) FROM person WHERE gender = 'male' )
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How old is the doctor named Zach?
|
SELECT age FROM Person WHERE job = 'doctor' AND name = 'Zach'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the age of the doctor named Zach?
|
SELECT age FROM Person WHERE job = 'doctor' AND name = 'Zach'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who is the person whose age is below 30?
|
SELECT name FROM Person WHERE age < 30
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the name of the person whose age is below 30?
|
SELECT name FROM Person WHERE age < 30
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many people whose age is greater 30 and job is engineer?
|
SELECT count(*) FROM Person WHERE age > 30 AND job = 'engineer'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
HOw many engineers are older than 30?
|
SELECT count(*) FROM Person WHERE age > 30 AND job = 'engineer'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the average age for each gender?
|
SELECT avg(age) , gender FROM Person GROUP BY gender
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How old is each gender, on average?
|
SELECT avg(age) , gender FROM Person GROUP BY gender
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is average age for different job title?
|
SELECT avg(age) , job FROM Person GROUP BY job
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How old is the average person for each job?
|
SELECT avg(age) , job FROM Person GROUP BY job
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is average age of male for different job title?
|
SELECT avg(age) , job FROM Person WHERE gender = 'male' GROUP BY job
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the average age for a male in each job?
|
SELECT avg(age) , job FROM Person WHERE gender = 'male' GROUP BY job
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is minimum age for different job title?
|
SELECT min(age) , job FROM Person GROUP BY job
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How old is the youngest person for each job?
|
SELECT min(age) , job FROM Person GROUP BY job
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the number of people who is under 40 for each gender.
|
SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many people are under 40 for each gender?
|
SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name of people whose age is greater than any engineer sorted by their age.
|
SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = 'engineer') ORDER BY age
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the name of all the people who are older than at least one engineer? Order them by age.
|
SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = 'engineer') ORDER BY age
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the number of people whose age is greater than all engineers.
|
SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = 'engineer')
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
How many people are older than every engineer?
|
SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = 'engineer')
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
list the name, job title of all people ordered by their names.
|
SELECT name , job FROM Person ORDER BY name
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names and job titles of every person ordered alphabetically by name?
|
SELECT name , job FROM Person ORDER BY name
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the names of all person sorted in the descending order using age.
|
SELECT name FROM Person ORDER BY age DESC
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of everybody sorted by age in descending order?
|
SELECT name FROM Person ORDER BY age DESC
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name and age of all males in order of their age.
|
SELECT name FROM Person WHERE gender = 'male' ORDER BY age
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the name and age of every male? Order the results by age.
|
SELECT name FROM Person WHERE gender = 'male' ORDER BY age
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name and age of the person who is a friend of both Dan and Alice.
|
SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice'
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names and ages of every person who is a friend of both Dan and Alice?
|
SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice'
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name and age of the person who is a friend of Dan or Alice.
|
SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' OR T2.friend = 'Alice'
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the different names and ages of every friend of either Dan or alice?
|
SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' OR T2.friend = 'Alice'
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name of the person who has friends with age above 40 and under age 30?
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of every person who has a friend over 40 and under 30?
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name of the person who has friends with age above 40 but not under age 30?
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of the people who are older 40 but no friends under age 30?
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name of the person who has no student friends.
|
SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = 'student'
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of the people who have no friends who are students?
|
SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = 'student'
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the person who has exactly one friend.
|
SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of everybody who has exactly one friend?
|
SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1
|
easy
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who are the friends of Bob?
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = 'Bob'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who are Bob's friends?
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = 'Bob'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name of persons who are friends with Bob.
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Bob'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of all of Bob's friends?
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Bob'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the names of females who are friends with Zach
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Zach' AND T1.gender = 'female'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of all females who are friends with Zach?
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Zach' AND T1.gender = 'female'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the female friends of Alice.
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'female'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are all the friends of Alice who are female?
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'female'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the male friend of Alice whose job is a doctor?
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'male' AND T1.job = 'doctor'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who are the friends of Alice that are doctors?
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'male' AND T1.job = 'doctor'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who has a friend that is from new york city?
|
SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = 'new york city'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of all friends who are from New York?
|
SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = 'new york city'
|
medium
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who has friends that are younger than the average age?
|
SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the different names of friends who are younger than the average age for a friend?
|
SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who has friends that are older than the average age? Print their friends and their ages as well
|
SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Whare the names, friends, and ages of all people who are older than the average age of a person?
|
SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person)
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who is the friend of Zach with longest year relationship?
|
SELECT friend FROM PersonFriend WHERE name = 'Zach' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Which friend of Zach has the longest-lasting friendship?
|
SELECT friend FROM PersonFriend WHERE name = 'Zach' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the age of the friend of Zach with longest year relationship?
|
SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Zach' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the ages of all of Zach's friends who are in the longest relationship?
|
SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Zach' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name of persons who are friends with Alice for the shortest years.
|
SELECT name FROM PersonFriend WHERE friend = 'Alice' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = 'Alice')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of all people who are friends with Alice for the shortest amount of time?
|
SELECT name FROM PersonFriend WHERE friend = 'Alice' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = 'Alice')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find the name, age, and job title of persons who are friends with Alice for the longest years.
|
SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = 'Alice')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names, ages, and jobs of all people who are friends with Alice for the longest amount of time?
|
SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = 'Alice')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Who is the person that has no friend?
|
SELECT name FROM person EXCEPT SELECT name FROM PersonFriend
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of all people who do not have friends?
|
SELECT name FROM person EXCEPT SELECT name FROM PersonFriend
|
hard
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Which person whose friends have the oldest average age?
|
SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the name of the person who has the oldest average age for their friends, and what is that average age?
|
SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the total number of people who has no friend living in the city of Austin.
|
SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = 'Austin')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What is the total number of people who have no friends living in Austin?
|
SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = 'Austin')
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
Find Alice's friends of friends.
|
SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = 'Alice' AND T4.name != 'Alice'
|
extra
|
CREATE TABLE Person (name text, age number, city text, gender text, job text); CREATE TABLE PersonFriend (name text, friend text, year number);
|
What are the names of all of Alice's friends of friends?
|
SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = 'Alice' AND T4.name != 'Alice'
|
extra
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
How many members are there?
|
SELECT count(*) FROM member
|
easy
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
List the names of members in ascending alphabetical order.
|
SELECT Name FROM member ORDER BY Name ASC
|
easy
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
What are the names and countries of members?
|
SELECT Name , Country FROM member
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the names of members whose country is "United States" or "Canada".
|
SELECT Name FROM member WHERE Country = "United States" OR Country = "Canada"
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the different countries and the number of members from each.
|
SELECT Country , COUNT(*) FROM member GROUP BY Country
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the most common country across members.
|
SELECT Country FROM member GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1
|
hard
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Which countries have more than two members?
|
SELECT Country FROM member GROUP BY Country HAVING COUNT(*) > 2
|
easy
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the leader names and locations of colleges.
|
SELECT Leader_Name , College_Location FROM college
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the names of members and names of colleges they go to.
|
SELECT T2.Name , T1.Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the names of members and the locations of colleges they go to in ascending alphabetical order of member names.
|
SELECT T2.Name , T1.College_Location FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID ORDER BY T2.Name ASC
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the distinct leader names of colleges associated with members from country "Canada".
|
SELECT DISTINCT T1.Leader_Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID WHERE T2.Country = "Canada"
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the names of members and the decoration themes they have.
|
SELECT T1.Name , T2.Decoration_Theme FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the names of members that have a rank in round higher than 3.
|
SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID WHERE T2.Rank_in_Round > 3
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
Show the names of members in ascending order of their rank in rounds.
|
SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID ORDER BY Rank_in_Round ASC
|
medium
|
CREATE TABLE college (College_ID number, Name text, Leader_Name text, College_Location text); CREATE TABLE member (Member_ID number, Name text, Country text, College_ID number); CREATE TABLE round (Round_ID number, Member_ID number, Decoration_Theme text, Rank_in_Round number);
|
List the names of members who did not participate in any round.
|
SELECT Name FROM member WHERE Member_ID NOT IN (SELECT Member_ID FROM round)
|
hard
|
CREATE TABLE Roles (role_code text, role_description text); CREATE TABLE Users (user_id number, role_code text, user_name text, user_login text, password text); CREATE TABLE Document_Structures (document_structure_code text, parent_document_structure_code text, document_structure_description text); CREATE TABLE Functional_Areas (functional_area_code text, parent_functional_area_code text, functional_area_description text); CREATE TABLE Images (image_id number, image_alt_text text, image_name text, image_url text); CREATE TABLE Documents (document_code text, document_structure_code text, document_type_code text, access_count number, document_name text); CREATE TABLE Document_Functional_Areas (document_code text, functional_area_code text); CREATE TABLE Document_Sections (section_id number, document_code text, section_sequence number, section_code text, section_title text); CREATE TABLE Document_Sections_Images (section_id number, image_id number);
|
Find the name and access counts of all documents, in alphabetic order of the document name.
|
SELECT document_name , access_count FROM documents ORDER BY document_name
|
medium
|
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