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Encontre as datas em que mais de uma revisão foi feita.
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CREATE TABLE Catalogs (date_of_latest_revision VARCHAR)
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SELECT date_of_latest_revision FROM Catalogs GROUP BY date_of_latest_revision HAVING COUNT(*) > 1
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Quantos produtos estão nos registos?
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CREATE TABLE catalog_contents (Id VARCHAR)
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SELECT COUNT(*) FROM catalog_contents
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Nomear todos os produtos com o ID de entrada seguinte superior a 8.
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CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, next_entry_id INTEGER)
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SELECT catalog_entry_name FROM catalog_contents WHERE next_entry_id > 8
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Quantos aviões temos?
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CREATE TABLE Aircraft (Id VARCHAR)
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SELECT COUNT(*) FROM Aircraft
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Mostrar o nome e a distância de todas as aeronaves.
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CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR)
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SELECT name, distance FROM Aircraft
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Mostrar identificação de todas as aeronaves com mais de 1000 distâncias.
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CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER)
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SELECT aid FROM Aircraft WHERE distance > 1000
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Quantos aviões têm distância entre 1000 e 5000?
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CREATE TABLE Aircraft (distance INTEGER)
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SELECT COUNT(*) FROM Aircraft WHERE distance BETWEEN 1000 AND 5000
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Qual é o nome e a distância para aeronaves com ID 12?
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CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR, aid VARCHAR)
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SELECT name, distance FROM Aircraft WHERE aid = 12
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Qual é a distância mínima, média e máxima de todas as aeronaves.
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CREATE TABLE Aircraft (distance INTEGER)
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SELECT MIN(distance), AVG(distance), MAX(distance) FROM Aircraft
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Indicar a identificação e o nome da aeronave com a distância máxima.
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CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR, distance VARCHAR)
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SELECT aid, name FROM Aircraft ORDER BY distance DESC LIMIT 1
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Mostrar o nome das aeronaves com as três distâncias mais baixas.
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CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR)
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SELECT name FROM Aircraft ORDER BY distance LIMIT 3
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Mostrar os nomes de todas as aeronaves com distâncias superiores à média.
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CREATE TABLE Aircraft (name VARCHAR, distance INTEGER)
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SELECT name FROM Aircraft WHERE distance > (SELECT AVG(distance) FROM Aircraft)
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Quantos empregados temos?
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CREATE TABLE Employee (Id VARCHAR)
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SELECT COUNT(*) FROM Employee
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Mostrar o nome e o salário de todos os empregados, ordenados por salário.
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CREATE TABLE Employee (name VARCHAR, salary VARCHAR)
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SELECT name, salary FROM Employee ORDER BY salary
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Mostrar identificação de todos os empregados com um salário de pelo menos 100000.
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CREATE TABLE Employee (eid VARCHAR, salary INTEGER)
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SELECT eid FROM Employee WHERE salary > 100000
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Quantos funcionários têm salário entre 100.000 e 200.000?
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CREATE TABLE Employee (salary INTEGER)
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SELECT COUNT(*) FROM Employee WHERE salary BETWEEN 100000 AND 200000
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Qual é o nome e o salário do empregado com o número 242518965?
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CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR)
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SELECT name, salary FROM Employee WHERE eid = 242518965
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Qual é o salário médio e máximo de todos os empregados.
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CREATE TABLE Employee (salary INTEGER)
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SELECT AVG(salary), MAX(salary) FROM Employee
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Indicar a identificação e o nome do empregado com o salário máximo.
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CREATE TABLE Employee (eid VARCHAR, name VARCHAR, salary VARCHAR)
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SELECT eid, name FROM Employee ORDER BY salary DESC LIMIT 1
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Indicar os nomes dos empregados com os três salários mais baixos.
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CREATE TABLE Employee (name VARCHAR, salary VARCHAR)
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SELECT name FROM Employee ORDER BY salary LIMIT 3
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Mostrar os nomes de todos os empregados com salário superior à média.
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CREATE TABLE Employee (name VARCHAR, salary INTEGER)
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SELECT name FROM Employee WHERE salary > (SELECT AVG(salary) FROM Employee)
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Mostra a identificação e o salário do Mark Young.
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CREATE TABLE Employee (eid VARCHAR, salary VARCHAR, name VARCHAR)
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SELECT eid, salary FROM Employee WHERE name = 'Mark Young'
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Quantos voos temos?
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CREATE TABLE Flight (Id VARCHAR)
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SELECT COUNT(*) FROM Flight
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Indicar o número do voo, a origem e o destino de todos os voos na ordem alfabética das cidades de partida.
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CREATE TABLE Flight (flno VARCHAR, origin VARCHAR, destination VARCHAR)
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SELECT flno, origin, destination FROM Flight ORDER BY origin
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Mostra o número de todos os voos de Los Angeles.
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CREATE TABLE Flight (flno VARCHAR, origin VARCHAR)
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SELECT flno FROM Flight WHERE origin = "Los Angeles"
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Mostrar a origem de todos os voos com destino em Honolulu.
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CREATE TABLE Flight (origin VARCHAR, destination VARCHAR)
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SELECT origin FROM Flight WHERE destination = "Honolulu"
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Mostra-me a data de partida e data de chegada de todos os voos de Los Angeles para Honolulu.
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CREATE TABLE Flight (departure_date VARCHAR, arrival_date VARCHAR, origin VARCHAR, destination VARCHAR)
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SELECT departure_date, arrival_date FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu"
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Indicar o número do voo para todos os voos com uma distância superior a 2000.
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CREATE TABLE Flight (flno VARCHAR, distance INTEGER)
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SELECT flno FROM Flight WHERE distance > 2000
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Qual é o preço médio de voos de Los Angeles para Honolulu?
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CREATE TABLE Flight (price INTEGER, origin VARCHAR, destination VARCHAR)
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SELECT AVG(price) FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu"
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Indicar origem e destino para voos com preço superior a 300.
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CREATE TABLE Flight (origin VARCHAR, destination VARCHAR, price INTEGER)
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SELECT origin, destination FROM Flight WHERE price > 300
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Indicar o número do voo e a distância do voo com o preço máximo.
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CREATE TABLE Flight (flno VARCHAR, distance VARCHAR, price VARCHAR)
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SELECT flno, distance FROM Flight ORDER BY price DESC LIMIT 1
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Indicar o número de voos dos voos com as três distâncias mais baixas.
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CREATE TABLE Flight (flno VARCHAR, distance VARCHAR)
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SELECT flno FROM Flight ORDER BY distance LIMIT 3
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Qual é a distância média e o preço médio para voos de Los Angeles.
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CREATE TABLE Flight (distance INTEGER, price INTEGER, origin VARCHAR)
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SELECT AVG(distance), AVG(price) FROM Flight WHERE origin = "Los Angeles"
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Indicar todas as origens e o número de voos de cada origem.
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CREATE TABLE Flight (origin VARCHAR)
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SELECT origin, COUNT(*) FROM Flight GROUP BY origin
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Indicar todos os destinos e o número de voos para cada destino.
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CREATE TABLE Flight (destination VARCHAR)
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SELECT destination, COUNT(*) FROM Flight GROUP BY destination
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Qual a origem que tem mais voos?
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CREATE TABLE Flight (origin VARCHAR)
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SELECT origin FROM Flight GROUP BY origin ORDER BY COUNT(*) DESC LIMIT 1
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Qual é o destino com menos voos?
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CREATE TABLE Flight (destination VARCHAR)
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SELECT destination FROM Flight GROUP BY destination ORDER BY COUNT(*) LIMIT 1
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Qual é o nome do avião do voo com o número 99 ?
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CREATE TABLE Flight (aid VARCHAR, flno VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR)
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SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99
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Mostrar todos os números de voos com aeronaves Airbus A340-300.
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CREATE TABLE Flight (flno VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
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SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300"
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Indicar os nomes das aeronaves e o número de voos de cada aeronave.
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CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR)
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SELECT T2.name, COUNT(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid
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Mostrar os nomes de todas as aeronaves com pelo menos dois voos.
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CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR)
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SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING COUNT(*) >= 2
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Quantos empregados têm certificado.
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CREATE TABLE Certificate (eid VARCHAR)
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SELECT COUNT(DISTINCT eid) FROM Certificate
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Mostre identificação para todos os funcionários que não têm certificado.
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CREATE TABLE Employee (eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR)
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SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate
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Mostrar os nomes de todas as aeronaves de que John Williams tem certificados.
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CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Employee (eid VARCHAR, name VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR)
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SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams"
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Mostrar os nomes de todos os empregados que têm certificado de Boeing 737-800.
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CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
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SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
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Mostrar os nomes de todos os empregados que possuem certificados tanto no Boeing 737-800 como no Airbus A340-300.
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CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
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SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300"
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Mostrar os nomes de todos os empregados que não têm certificado de Boeing 737-800.
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CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Employee (name VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
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SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
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Indicar o nome da aeronave cujo certificado tenha sido emitido por menos pessoas.
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CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR)
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SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY COUNT(*) DESC LIMIT 1
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Indicar o nome e a distância dos aviões com mais de 5000 distâncias e que tenham pelo menos 5 pessoas com o seu certificado.
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CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR, distance INTEGER)
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SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY COUNT(*) >= 5
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Qual é o salário e o nome do empregado que tem o maior número de certificados de aeronave?
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CREATE TABLE Certificate (eid VARCHAR); CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR)
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SELECT T1.name, T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1
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Qual é o salário e o nome do empregado que tem o maior número de certificados em aeronaves com distância superior a 5000?
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CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR)
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SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1
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Quantas alergias há?
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CREATE TABLE Allergy_type (allergy VARCHAR)
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SELECT COUNT(DISTINCT allergy) FROM Allergy_type
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Quantos tipos diferentes de alergia existem?
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CREATE TABLE Allergy_type (allergytype VARCHAR)
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SELECT COUNT(DISTINCT allergytype) FROM Allergy_type
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Mostre todos os tipos de alergia.
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CREATE TABLE Allergy_type (allergytype VARCHAR)
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SELECT DISTINCT allergytype FROM Allergy_type
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Mostre todas as alergias e os seus tipos.
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CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
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SELECT allergy, allergytype FROM Allergy_type
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Mostre todas as alergias com alimentos.
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CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
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SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"
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Qual é o tipo de alergia do gato?
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CREATE TABLE Allergy_type (allergytype VARCHAR, allergy VARCHAR)
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SELECT allergytype FROM Allergy_type WHERE allergy = "Cat"
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Quantas alergias têm tipo animal?
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CREATE TABLE Allergy_type (allergytype VARCHAR)
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SELECT COUNT(*) FROM Allergy_type WHERE allergytype = "animal"
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Mostrar todos os tipos de alergia e o número de alergias em cada tipo.
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CREATE TABLE Allergy_type (allergytype VARCHAR)
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SELECT allergytype, COUNT(*) FROM Allergy_type GROUP BY allergytype
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Que tipo de alergia tem mais alérgicas?
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CREATE TABLE Allergy_type (allergytype VARCHAR)
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SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) DESC LIMIT 1
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Qual tipo de alergia tem menos alergias?
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CREATE TABLE Allergy_type (allergytype VARCHAR)
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SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) LIMIT 1
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Quantos alunos há?
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CREATE TABLE Student (Id VARCHAR)
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SELECT COUNT(*) FROM Student
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Mostrar nome e apelido de todos os alunos.
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CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR)
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SELECT Fname, Lname FROM Student
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Quantos conselheiros diferentes estão listados?
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CREATE TABLE Student (advisor VARCHAR)
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SELECT COUNT(DISTINCT advisor) FROM Student
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Mostra todos os grandes.
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CREATE TABLE Student (Major VARCHAR)
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SELECT DISTINCT Major FROM Student
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Mostre todas as cidades onde vivem os estudantes.
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CREATE TABLE Student (city_code VARCHAR)
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SELECT DISTINCT city_code FROM Student
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Mostrar nome, apelido, idade de todas as estudantes do sexo feminino.
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CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Sex VARCHAR)
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SELECT Fname, Lname, Age FROM Student WHERE Sex = 'F'
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Mostrar identificação de estudante para todos os estudantes do sexo masculino.
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CREATE TABLE Student (StuID VARCHAR, Sex VARCHAR)
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SELECT StuID FROM Student WHERE Sex = 'M'
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Quantos alunos têm 18 anos?
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CREATE TABLE Student (age VARCHAR)
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SELECT COUNT(*) FROM Student WHERE age = 18
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Mostre todos os documentos de estudantes com mais de 20 anos.
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CREATE TABLE Student (StuID VARCHAR, age INTEGER)
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SELECT StuID FROM Student WHERE age > 20
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Em qual cidade o estudante cujo sobrenome é "Kim" mora?
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CREATE TABLE Student (city_code VARCHAR, LName VARCHAR)
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SELECT city_code FROM Student WHERE LName = "Kim"
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Quem é o conselheiro de um estudante com identificação 1004?
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CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR)
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SELECT Advisor FROM Student WHERE StuID = 1004
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Quantos estudantes vivem no HKG ou no CHI?
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CREATE TABLE Student (city_code VARCHAR)
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SELECT COUNT(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI"
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Mostrar a idade mínima, média e máxima de todos os alunos.
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CREATE TABLE Student (age INTEGER)
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SELECT MIN(age), AVG(age), MAX(age) FROM Student
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Qual é o nome do aluno mais novo?
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CREATE TABLE Student (LName VARCHAR, age INTEGER)
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SELECT LName FROM Student WHERE age = (SELECT MIN(age) FROM Student)
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Mostre a identificação do estudante mais velho.
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CREATE TABLE Student (StuID VARCHAR, age INTEGER)
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SELECT StuID FROM Student WHERE age = (SELECT MAX(age) FROM Student)
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Mostre todos os cursos e o número correspondente de estudantes.
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CREATE TABLE Student (major VARCHAR)
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SELECT major, COUNT(*) FROM Student GROUP BY major
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Qual é a especialidade que tem mais alunos?
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CREATE TABLE Student (major VARCHAR)
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SELECT major FROM Student GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1
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Mostrar todas as idades e o número correspondente de alunos.
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CREATE TABLE Student (age VARCHAR)
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SELECT age, COUNT(*) FROM Student GROUP BY age
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Indicar a idade média dos estudantes do sexo masculino e feminino.
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CREATE TABLE Student (sex VARCHAR, age INTEGER)
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SELECT AVG(age), sex FROM Student GROUP BY sex
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Mostrar todas as cidades e o número correspondente de estudantes.
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CREATE TABLE Student (city_code VARCHAR)
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SELECT city_code, COUNT(*) FROM Student GROUP BY city_code
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Mostrar todos os orientadores e o número correspondente de alunos.
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CREATE TABLE Student (advisor VARCHAR)
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SELECT advisor, COUNT(*) FROM Student GROUP BY advisor
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Qual conselheiro tem mais alunos?
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CREATE TABLE Student (advisor VARCHAR)
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SELECT advisor FROM Student GROUP BY advisor ORDER BY COUNT(*) DESC LIMIT 1
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Quantos alunos têm alergia a gatos?
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CREATE TABLE Has_allergy (Allergy VARCHAR)
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SELECT COUNT(*) FROM Has_allergy WHERE Allergy = "Cat"
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Mostre todos os documentos de estudantes que têm pelo menos duas alergias.
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CREATE TABLE Has_allergy (StuID VARCHAR)
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SELECT StuID FROM Has_allergy GROUP BY StuID HAVING COUNT(*) >= 2
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Quais são as identidades dos estudantes que não têm alergias?
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CREATE TABLE Has_allergy (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR)
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SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy
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Quantas estudantes têm alergia ao leite ou aos ovos?
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CREATE TABLE Student (StuID VARCHAR, sex VARCHAR); CREATE TABLE has_allergy (StuID VARCHAR, allergy VARCHAR)
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SELECT COUNT(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs"
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Quantos alunos têm uma alergia alimentar?
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CREATE TABLE Has_allergy (allergy VARCHAR); CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
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SELECT COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food"
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Qual a alergia que mais afeta estudantes?
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CREATE TABLE Has_allergy (Allergy VARCHAR)
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SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY COUNT(*) DESC LIMIT 1
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Mostre todas as alergias com o número de alunos afetados.
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CREATE TABLE Has_allergy (Allergy VARCHAR)
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SELECT Allergy, COUNT(*) FROM Has_allergy GROUP BY Allergy
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Mostrar todos os tipos de alergia com o número de alunos afetados.
|
CREATE TABLE Has_allergy (allergy VARCHAR); CREATE TABLE Allergy_type (allergytype VARCHAR, allergy VARCHAR)
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SELECT T2.allergytype, COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype
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Encontre o nome e idade do aluno que tem alergia ao leite e ao gato.
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CREATE TABLE Has_allergy (lname VARCHAR, age VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Student (lname VARCHAR, age VARCHAR, StuID VARCHAR, Allergy VARCHAR)
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SELECT lname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
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Quais são as alergias e seus tipos que a aluna de primeiro nome Lisa tem? E ordena o resultado pelo nome das alergias.
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CREATE TABLE Has_allergy (Allergy VARCHAR, StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR, Fname VARCHAR); CREATE TABLE Allergy_type (Allergy VARCHAR, AllergyType VARCHAR)
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SELECT T1.Allergy, T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy
|
Encontre o nome e o sexo do aluno que tem alergia ao leite, mas não ao gato.
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CREATE TABLE Student (fname VARCHAR, sex VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Has_allergy (fname VARCHAR, sex VARCHAR, StuID VARCHAR, Allergy VARCHAR)
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SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat")
|
Encontre a idade média dos alunos que têm alergias a alimentos e tipos de animais.
|
CREATE TABLE Student (age INTEGER, StuID VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR)
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SELECT AVG(age) FROM Student WHERE StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal")
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Escreva o nome e apelido dos alunos que não têm qualquer tipo de alergia alimentar.
|
CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR)
|
SELECT fname, lname FROM Student WHERE NOT StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
|
Encontre o número de estudantes do sexo masculino (sexo é 'M') que têm alguma alergia ao tipo de alimento.
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CREATE TABLE Has_allergy (Allergy VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Student (sex VARCHAR, StuID VARCHAR)
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SELECT COUNT(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food")
|
Encontre os nomes e cidades dos alunos que têm alergia ao leite ou ao gato.
|
CREATE TABLE Has_Allergy (stuid VARCHAR, Allergy VARCHAR); CREATE TABLE Student (fname VARCHAR, city_code VARCHAR, stuid VARCHAR)
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SELECT DISTINCT T1.fname, T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat"
|
Encontre o número de estudantes com mais de 18 anos e que não tenham alergia a alimentos ou animais.
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CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (Allergy VARCHAR); CREATE TABLE Student (age VARCHAR, StuID VARCHAR)
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SELECT COUNT(*) FROM Student WHERE age > 18 AND NOT StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal")
|
Encontre o nome e a especialidade dos alunos que não são alegrias para a soja.
|
CREATE TABLE Has_allergy (fname VARCHAR, major VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Student (fname VARCHAR, major VARCHAR, StuID VARCHAR, Allergy VARCHAR)
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SELECT fname, major FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy")
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