premise
stringlengths 923
1.41k
| hypothesis
stringlengths 11
33
| label
stringclasses 4
values |
|---|---|---|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Kilian is loyal.
|
neutral
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is not gentle.
|
entailment
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is not cheeky.
|
entailment
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Aidan is not smart.
|
contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is not loyal.
|
self_contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Kilian is not cheeky.
|
self_contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Kilian is smart.
|
contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Bud is loyal.
|
contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Aidan is rich.
|
self_contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Aidan is gentle.
|
contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Rosie is not popular.
|
entailment
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is gentle.
|
contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Rosie is gentle.
|
neutral
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is popular.
|
entailment
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is rich.
|
self_contradiction
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Rosie is not gentle.
|
neutral
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Rosie is not cheeky.
|
neutral
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Kilian is gentle.
|
neutral
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is smart.
|
entailment
|
Kilian is not smart.
Aidan is rich.
Kilian is cheeky.
Harris is gentle.
Bud is not gentle.
Olaf is not smart.
Bud is not loyal.
Dave is not gentle.
Harris is not rich.
Bud is not popular.
Aidan is smart.
Dave is not cheeky.If Kilian is not smart, then Kilian is not cheeky and Dave is popular.
If there is someone who is not loyal, then Dave is not gentle and Dave is rich.
If there is someone who is not rich, then Rosie is not popular and Olaf is not cheeky.
Someone who is not cheeky and not rich is always smart and popular.
Someone is loyal and not gentle if and only if he is rich.
Someone who is not popular is always smart.
If there is someone who is either not gentle or not smart, then Aidan is popular.
If everyone is not gentle or loyal, then Aidan is not smart.
Someone who is both not cheeky and loyal is always smart.
Someone is not rich and smart if and only if he is not loyal and popular.
Harris being not loyal is equivalent to Kilian being cheeky and Kilian being popular.
Someone who is eithor popular or loyal is always not rich.
|
Dave is loyal.
|
self_contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Ramsey is skinny.
|
entailment
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Ramsey is not harsh.
|
self_contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Ramsey is cheeky.
|
entailment
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Isaiah is harsh.
|
contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Vicki is not remarkable.
|
entailment
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Igor is administrative.
|
neutral
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Isaiah is not cold.
|
contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Curt is skinny.
|
contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Curt is cheeky.
|
neutral
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Isaiah is not administrative.
|
neutral
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Igor is harsh.
|
contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Ramsey is not cold.
|
entailment
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Vicki is cheeky.
|
self_contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Isaiah is not skinny.
|
neutral
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Ramsey is administrative.
|
contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Carter is cheeky.
|
neutral
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Ramsey is harsh.
|
self_contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Vicki is not cold.
|
entailment
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Igor is cheeky.
|
self_contradiction
|
Vicki is not cold.
Ramsey is harsh.
Della is not cold.
Curt is cold.
Isaiah is not harsh.
Della is administrative.
Igor is not remarkable.
Isaiah is cold.
Della is not cheeky.
Ramsey is not administrative.
Della is skinny.
Curt is not skinny.It can be concluded that Vicki is administrative once knowing that Igor is not skinny.
If there is at least one people who is both harsh and not skinny, then Isaiah is cheeky.
If someone is harsh, then he is both not cold and cheeky.
It can be concluded that Igor is cheeky once knowing that Curt is harsh and Della is cold.
Someone who is not remarkable is always both not harsh and not cheeky.
If there is nobody who is not administrative, then Curt is not harsh.
If there is someone who is either cheeky or cold, then Vicki is not remarkable.
If there is someone who is not administrative, then Carter is not cold and Curt is remarkable.
Someone is cheeky if and only if he is not harsh.
If Isaiah is cheeky or Della is not cold, then Ramsey is skinny.
Carter is not remarkable if and only if Vicki is not cheeky and Della is cold.
If there is someone who is both not cheeky and cold, then Della is remarkable.
|
Igor is not cheeky.
|
self_contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Cadman is not loyal.
|
neutral
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Travis is red.
|
self_contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Gemma is not red.
|
entailment
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Cadman is not sufficient.
|
entailment
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Cadman is not cloudy.
|
neutral
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Cadman is wrong.
|
neutral
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Brooke is not happy.
|
self_contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Cadman is sufficient.
|
contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Rick is not loyal.
|
contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Brooke is happy.
|
self_contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Brooke is not wrong.
|
entailment
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Arthur is not wrong.
|
entailment
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Brooke is sufficient.
|
contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Rick is not cloudy.
|
self_contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Gemma is not wrong.
|
neutral
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Gemma is loyal.
|
neutral
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Cadman is happy.
|
contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Gemma is not cloudy.
|
self_contradiction
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Gemma is not sufficient.
|
entailment
|
Travis is not sufficient.
Travis is red.
Gemma is not sufficient.
Rick is not wrong.
Arthur is not wrong.
Cuthbert is not sufficient.
Rick is happy.
Travis is cloudy.
Gemma is not red.
Cadman is not happy.
Gemma is happy.
Brooke is not happy.Someone is sufficient and cloudy if and only if he is loyal.
If Gemma is not cloudy or Cuthbert is wrong, then Cadman is not sufficient.
Someone being happy is equivalent to being cloudy.
If Gemma is not red, then Brooke is not wrong, and vice versa.
If Travis is not cloudy or Travis is wrong, then Brooke is not sufficient.
If all people are not red, then Arthur is cloudy and Gemma is not sufficient.
If there is someone who is loyal, then Brooke is not red.
Someone is not red and not cloudy if and only if he is happy.
Someone who is not red or not wrong is always cloudy and not happy.
It can be concluded that Travis is wrong once knowing that Gemma is red.
If Travis is not wrong or Gemma is not cloudy, then Brooke is red.
If there is at least one people who is cloudy, then Cuthbert is not happy and Rick is sufficient.
|
Rick is red.
|
contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Stella is shiny.
|
self_contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Trent is not shiny.
|
entailment
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Brice is not beautiful.
|
entailment
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Stella is not frightened.
|
neutral
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Stella is not miniscule.
|
neutral
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Stella is beautiful.
|
entailment
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Stella is adorable.
|
contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Trent is shiny.
|
contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Gilroy is not beautiful.
|
self_contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Gilroy is beautiful.
|
self_contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Marion is not beautiful.
|
contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Marcus is not adorable.
|
self_contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Gilroy is frightened.
|
neutral
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Brice is adorable.
|
neutral
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Herman is not frightened.
|
neutral
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Gilroy is lonely.
|
contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Marcus is not beautiful.
|
contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Marcus is adorable.
|
self_contradiction
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Marion is beautiful.
|
entailment
|
Gilroy is miniscule.
Marion is not shiny.
Stella is shiny.
Stella is beautiful.
Marcus is adorable.
Herman is shiny.
Marion is not lonely.
Marcus is beautiful.
Trent is not shiny.
Gilroy is not beautiful.
Herman is adorable.
Brice is not beautiful.It can be concluded that Stella is not shiny and Marion is not frightened once knowing that Herman is not miniscule.
Someone is beautiful if and only if he is not shiny.
If there is someone who is not adorable, then Gilroy is beautiful and Trent is frightened.
Someone is not adorable and not shiny if and only if he is beautiful.
If someone is both miniscule and not lonely, then he is beautiful.
Trent is adorable if and only if Marion is beautiful and Marcus is not frightened.
If everyone is not frightened, then Gilroy is miniscule.
Brice being not lonely is equivalent to Brice being beautiful.
If someone is miniscule, then he is not lonely, and vice versa.
It can be concluded that Stella is not shiny once knowing that Marion is not miniscule and Stella is beautiful.
Someone being adorable is equivalent to being not miniscule.
If there is at least one people who is not shiny or not frightened, then Herman is lonely.
|
Marion is miniscule.
|
entailment
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Joshua is mad.
|
self_contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Quade is adorable.
|
contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Joshua is adorable.
|
self_contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Shelley is not funny.
|
neutral
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Hadden is inner.
|
entailment
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Pierce is funny.
|
entailment
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Joshua is inner.
|
self_contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Shelley is not weary.
|
neutral
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Pierce is mad.
|
contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Renfred is adorable.
|
entailment
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Timothy is successful.
|
neutral
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Timothy is not weary.
|
neutral
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Shelley is not inner.
|
neutral
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Joshua is not mad.
|
self_contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Pierce is inner.
|
contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Renfred is inner.
|
contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Joshua is not weary.
|
self_contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Pierce is not funny.
|
contradiction
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Shelley is not successful.
|
entailment
|
Quade is not adorable.
Joshua is inner.
Timothy is not funny.
Pierce is adorable.
Hadden is adorable.
Quade is not successful.
Shelley is not successful.
Joshua is not weary.
Hadden is inner.
Pierce is not mad.
Hadden is mad.
Quade is not funny.Someone being both funny and successful is equivalent to being adorable and not inner.
Timothy being not mad or Pierce being weary implies that Shelley is funny.
It can be concluded that Hadden is successful once knowing that Hadden is not funny or Shelley is not weary.
If Pierce is not weary and Quade is not funny, then Shelley is not adorable and Timothy is inner, and vice versa.
Someone who is not mad is always both funny and not weary.
Someone being both adorable and not inner is equivalent to being not weary.
If someone is not adorable and not funny, then he is inner, and vice versa.
If someone is funny and adorable, then he is not mad, and vice versa.
Someone is not funny and adorable if and only if he is mad and weary.
If someone who is successful is also not inner, then he is adorable.
If there is at least one people who is not mad, then Hadden is successful and Renfred is not weary.
If Joshua is not weary or Shelley is funny, then Hadden is inner.
|
Pierce is not weary.
|
entailment
|
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