Datasets:
Hawk28
/
spider-sql-prompts

Dataset card Data Studio Files Community
1
db_name
stringclasses
146 values
prompt
stringlengths
310
4.81k
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are card ids, customer ids, card types, and card numbers for each customer card? # ### SQL: # # SELECT card_id , customer_id , card_type_code , card_number FROM Customers_cards # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show the date valid from and the date valid to for the card with card number '4560596484842'. # ### SQL: # # SELECT date_valid_from , date_valid_to FROM Customers_cards WHERE card_number = "4560596484842" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the valid from and valid to dates for the card with the number 4560596484842? # ### SQL: # # SELECT date_valid_from , date_valid_to FROM Customers_cards WHERE card_number = "4560596484842" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What is the first name, last name, and phone of the customer with card 4560596484842. # ### SQL: # # SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.card_number = "4560596484842" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Return the full name and phone of the customer who has card number 4560596484842. # ### SQL: # # SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.card_number = "4560596484842" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # How many cards does customer Art Turcotte have? # ### SQL: # # SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Count the number of cards the customer with the first name Art and last name Turcotte has. # ### SQL: # # SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # How many debit cards do we have? # ### SQL: # # SELECT count(*) FROM Customers_cards WHERE card_type_code = "Debit" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Count the number of customer cards of the type Debit. # ### SQL: # # SELECT count(*) FROM Customers_cards WHERE card_type_code = "Debit" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # How many credit cards does customer Blanche Huels have? # ### SQL: # # SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Blanche" AND T2.customer_last_name = "Huels" AND T1.card_type_code = "Credit" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Count the number of credit cards that the customer with first name Blanche and last name Huels has. # ### SQL: # # SELECT count(*) FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Blanche" AND T2.customer_last_name = "Huels" AND T1.card_type_code = "Credit" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show all customer ids and the number of cards owned by each customer. # ### SQL: # # SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different customer ids, and how many cards does each one hold? # ### SQL: # # SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What is the customer id with most number of cards, and how many does he have? # ### SQL: # # SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Return the id of the customer who has the most cards, as well as the number of cards. # ### SQL: # # SELECT customer_id , count(*) FROM Customers_cards GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show id, first and last names for all customers with at least two cards. # ### SQL: # # SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the ids and full names of customers who hold two or more cards? # ### SQL: # # SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What is the customer id, first and last name with least number of accounts. # ### SQL: # # SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Return the id and full name of the customer who has the fewest accounts. # ### SQL: # # SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show all card type codes and the number of cards in each type. # ### SQL: # # SELECT card_type_code , count(*) FROM Customers_cards GROUP BY card_type_code # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different card types, and how many cards are there of each? # ### SQL: # # SELECT card_type_code , count(*) FROM Customers_cards GROUP BY card_type_code # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What is the card type code with most number of cards? # ### SQL: # # SELECT card_type_code FROM Customers_cards GROUP BY card_type_code ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Return the code of the card type that is most common. # ### SQL: # # SELECT card_type_code FROM Customers_cards GROUP BY card_type_code ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show card type codes with at least 5 cards. # ### SQL: # # SELECT card_type_code FROM Customers_cards GROUP BY card_type_code HAVING count(*) >= 5 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the codes of card types that have 5 or more cards? # ### SQL: # # SELECT card_type_code FROM Customers_cards GROUP BY card_type_code HAVING count(*) >= 5 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show all card type codes and the number of customers holding cards in each type. # ### SQL: # # SELECT card_type_code , count(DISTINCT customer_id) FROM Customers_cards GROUP BY card_type_code # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different card type codes, and how many different customers hold each type? # ### SQL: # # SELECT card_type_code , count(DISTINCT customer_id) FROM Customers_cards GROUP BY card_type_code # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show the customer ids and firstname without a credit card. # ### SQL: # # SELECT customer_id , customer_first_name FROM Customers EXCEPT SELECT T1.customer_id , T2.customer_first_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE card_type_code = "Credit" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the ids and first names of customers who do not hold a credit card? # ### SQL: # # SELECT customer_id , customer_first_name FROM Customers EXCEPT SELECT T1.customer_id , T2.customer_first_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE card_type_code = "Credit" # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show all card type codes. # ### SQL: # # SELECT DISTINCT card_type_code FROM Customers_Cards # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different card type codes? # ### SQL: # # SELECT DISTINCT card_type_code FROM Customers_Cards # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show the number of card types. # ### SQL: # # SELECT count(DISTINCT card_type_code) FROM Customers_Cards # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # How many different card types are there? # ### SQL: # # SELECT count(DISTINCT card_type_code) FROM Customers_Cards # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show all transaction types. # ### SQL: # # SELECT DISTINCT transaction_type FROM Financial_Transactions # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different types of transactions? # ### SQL: # # SELECT DISTINCT transaction_type FROM Financial_Transactions # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show the number of transaction types. # ### SQL: # # SELECT count(DISTINCT transaction_type) FROM Financial_Transactions # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # How many different types of transactions are there? # ### SQL: # # SELECT count(DISTINCT transaction_type) FROM Financial_Transactions # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What is the average and total transaction amount? # ### SQL: # # SELECT avg(transaction_amount) , sum(transaction_amount) FROM Financial_transactions # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Return the average transaction amount, as well as the total amount of all transactions. # ### SQL: # # SELECT avg(transaction_amount) , sum(transaction_amount) FROM Financial_transactions # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show the card type codes and the number of transactions. # ### SQL: # # SELECT T2.card_type_code , count(*) FROM Financial_transactions AS T1 JOIN Customers_cards AS T2 ON T1.card_id = T2.card_id GROUP BY T2.card_type_code # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different card types, and how many transactions have been made with each? # ### SQL: # # SELECT T2.card_type_code , count(*) FROM Financial_transactions AS T1 JOIN Customers_cards AS T2 ON T1.card_id = T2.card_id GROUP BY T2.card_type_code # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show the transaction type and the number of transactions. # ### SQL: # # SELECT transaction_type , count(*) FROM Financial_transactions GROUP BY transaction_type # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different transaction types, and how many transactions of each have taken place? # ### SQL: # # SELECT transaction_type , count(*) FROM Financial_transactions GROUP BY transaction_type # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What is the transaction type that has processed the greatest total amount in transactions? # ### SQL: # # SELECT transaction_type FROM Financial_transactions GROUP BY transaction_type ORDER BY sum(transaction_amount) DESC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Return the type of transaction with the highest total amount. # ### SQL: # # SELECT transaction_type FROM Financial_transactions GROUP BY transaction_type ORDER BY sum(transaction_amount) DESC LIMIT 1 # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # Show the account id and the number of transactions for each account # ### SQL: # # SELECT account_id , count(*) FROM Financial_transactions GROUP BY account_id # ### End.
customers_card_transactions
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Accounts ( account_id, customer_id, account_name, other_account_details ) # Customers ( customer_id, customer_first_name, customer_last_name, customer_address, customer_phone, customer_email, other_customer_details ) # Customers_Cards ( card_id, customer_id, card_type_code, card_number, date_valid_from, date_valid_to, other_card_details ) # Financial_Transactions ( transaction_id, previous_transaction_id, account_id, card_id, transaction_type, transaction_date, transaction_amount, transaction_comment, other_transaction_details ) # # Financial_Transactions.account_id can be joined with Accounts.account_id # Financial_Transactions.card_id can be joined with Customers_Cards.card_id # ### Question: # # What are the different account ids that have made financial transactions, as well as how many transactions correspond to each? # ### SQL: # # SELECT account_id , count(*) FROM Financial_transactions GROUP BY account_id # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # How many tracks do we have? # ### SQL: # # SELECT count(*) FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Count the number of tracks. # ### SQL: # # SELECT count(*) FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show the name and location for all tracks. # ### SQL: # # SELECT name , LOCATION FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names and locations of all tracks? # ### SQL: # # SELECT name , LOCATION FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show names and seatings, ordered by seating for all tracks opened after 2000. # ### SQL: # # SELECT name , seating FROM track WHERE year_opened > 2000 ORDER BY seating # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names and seatings for all tracks opened after 2000, ordered by seating? # ### SQL: # # SELECT name , seating FROM track WHERE year_opened > 2000 ORDER BY seating # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What is the name, location and seating for the most recently opened track? # ### SQL: # # SELECT name , LOCATION , seating FROM track ORDER BY year_opened DESC LIMIT 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Return the name, location, and seating of the track that was opened in the most recent year. # ### SQL: # # SELECT name , LOCATION , seating FROM track ORDER BY year_opened DESC LIMIT 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What is the minimum, maximum, and average seating for all tracks. # ### SQL: # # SELECT min(seating) , max(seating) , avg(seating) FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Return the minimum, maximum, and average seating across all tracks. # ### SQL: # # SELECT min(seating) , max(seating) , avg(seating) FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show the name, location, open year for all tracks with a seating higher than the average. # ### SQL: # # SELECT name , LOCATION , year_opened FROM track WHERE seating > (SELECT avg(seating) FROM track) # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names, locations, and years of opening for tracks with seating higher than average? # ### SQL: # # SELECT name , LOCATION , year_opened FROM track WHERE seating > (SELECT avg(seating) FROM track) # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are distinct locations where tracks are located? # ### SQL: # # SELECT DISTINCT LOCATION FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Give the different locations of tracks. # ### SQL: # # SELECT DISTINCT LOCATION FROM track # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # How many races are there? # ### SQL: # # SELECT count(*) FROM race # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Count the number of races. # ### SQL: # # SELECT count(*) FROM race # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the distinct classes that races can have? # ### SQL: # # SELECT DISTINCT CLASS FROM race # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Return the different classes of races. # ### SQL: # # SELECT DISTINCT CLASS FROM race # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show name, class, and date for all races. # ### SQL: # # SELECT name , CLASS , date FROM race # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names, classes, and dates for all races? # ### SQL: # # SELECT name , CLASS , date FROM race # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show the race class and number of races in each class. # ### SQL: # # SELECT CLASS , count(*) FROM race GROUP BY CLASS # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the different classes of races, and how many races correspond to each? # ### SQL: # # SELECT CLASS , count(*) FROM race GROUP BY CLASS # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What is the race class with most number of races. # ### SQL: # # SELECT CLASS FROM race GROUP BY CLASS ORDER BY count(*) DESC LIMIT 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Give the class of races that is most common. # ### SQL: # # SELECT CLASS FROM race GROUP BY CLASS ORDER BY count(*) DESC LIMIT 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # List the race class with at least two races. # ### SQL: # # SELECT CLASS FROM race GROUP BY CLASS HAVING count(*) >= 2 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the classes of races that have two or more corresponding races? # ### SQL: # # SELECT CLASS FROM race GROUP BY CLASS HAVING count(*) >= 2 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names for tracks without a race in class 'GT'. # ### SQL: # # SELECT name FROM track EXCEPT SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id WHERE T1.class = 'GT' # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Give the names of tracks that do not have a race in the class 'GT'. # ### SQL: # # SELECT name FROM track EXCEPT SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id WHERE T1.class = 'GT' # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show all track names that have had no races. # ### SQL: # # SELECT name FROM track WHERE track_id NOT IN (SELECT track_id FROM race) # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Return the names of tracks that have no had any races. # ### SQL: # # SELECT name FROM track WHERE track_id NOT IN (SELECT track_id FROM race) # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show year where a track with a seating at least 5000 opened and a track with seating no more than 4000 opened. # ### SQL: # # SELECT year_opened FROM track WHERE seating BETWEEN 4000 AND 5000 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the years of opening for tracks with seating between 4000 and 5000? # ### SQL: # # SELECT year_opened FROM track WHERE seating BETWEEN 4000 AND 5000 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show the name of track and the number of races in each track. # ### SQL: # # SELECT T2.name , count(*) FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names of different tracks, and how many races has each had? # ### SQL: # # SELECT T2.name , count(*) FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show the name of track with most number of races. # ### SQL: # # SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id ORDER BY count(*) DESC LIMIT 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What is the name of the track that has had the greatest number of races? # ### SQL: # # SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id ORDER BY count(*) DESC LIMIT 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show the name and date for each race and its track name. # ### SQL: # # SELECT T1.name , T1.date , T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names and dates of races, and the names of the tracks where they are held? # ### SQL: # # SELECT T1.name , T1.date , T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Show the name and location of track with 1 race. # ### SQL: # # SELECT T2.name , T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id HAVING count(*) = 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the names and locations of tracks that have had exactly 1 race? # ### SQL: # # SELECT T2.name , T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id HAVING count(*) = 1 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # Find the locations where have both tracks with more than 90000 seats and tracks with less than 70000 seats. # ### SQL: # # SELECT LOCATION FROM track WHERE seating > 90000 INTERSECT SELECT LOCATION FROM track WHERE seating < 70000 # ### End.
race_track
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # race ( Race_ID, Name, Class, Date, Track_ID ) # track ( Track_ID, Name, Location, Seating, Year_Opened ) # # race.Track_ID can be joined with track.Track_ID # ### Question: # # What are the locations that have both tracks with more than 90000 seats, and tracks with fewer than 70000 seats? # ### SQL: # # SELECT LOCATION FROM track WHERE seating > 90000 INTERSECT SELECT LOCATION FROM track WHERE seating < 70000 # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # How many members have the black membership card? # ### SQL: # # SELECT count(*) FROM member WHERE Membership_card = 'Black' # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Find the number of members living in each address. # ### SQL: # # SELECT count(*) , address FROM member GROUP BY address # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Give me the names of members whose address is in Harford or Waterbury. # ### SQL: # # SELECT name FROM member WHERE address = 'Harford' OR address = 'Waterbury' # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Find the ids and names of members who are under age 30 or with black membership card. # ### SQL: # # SELECT name , member_id FROM member WHERE Membership_card = 'Black' OR age < 30 # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Find the purchase time, age and address of each member, and show the results in the order of purchase time. # ### SQL: # # SELECT Time_of_purchase , age , address FROM member ORDER BY Time_of_purchase # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Which membership card has more than 5 members? # ### SQL: # # SELECT Membership_card FROM member GROUP BY Membership_card HAVING count(*) > 5 # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Which address has both members younger than 30 and members older than 40? # ### SQL: # # SELECT address FROM member WHERE age < 30 INTERSECT SELECT address FROM member WHERE age > 40 # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # What is the membership card held by both members living in Hartford and ones living in Waterbury address? # ### SQL: # # SELECT membership_card FROM member WHERE address = 'Hartford' INTERSECT SELECT membership_card FROM member WHERE address = 'Waterbury' # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # How many members are not living in Hartford? # ### SQL: # # SELECT count(*) FROM member WHERE address != 'Hartford' # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Which address do not have any member with the black membership card? # ### SQL: # # SELECT address FROM member EXCEPT SELECT address FROM member WHERE Membership_card = 'Black' # ### End.
coffee_shop
### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # shop ( Shop_ID, Address, Num_of_staff, Score, Open_Year ) # member ( Member_ID, Name, Membership_card, Age, Time_of_purchase, Level_of_membership, Address ) # happy_hour ( HH_ID, Shop_ID, Month, Num_of_shaff_in_charge ) # happy_hour_member ( HH_ID, Member_ID, Total_amount ) # # happy_hour.Shop_ID can be joined with shop.Shop_ID # happy_hour_member.Member_ID can be joined with member.Member_ID # ### Question: # # Show the shop addresses ordered by their opening year. # ### SQL: # # SELECT address FROM shop ORDER BY open_year # ### End.