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Hawk28
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spider-sql-prompts

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train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the policy types more than 4 customers use. Show their type code. # ### SQL: # # SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING count(*) > 4 # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the total and average amount of settlements. # ### SQL: # # SELECT sum(settlement_amount) , avg(settlement_amount) FROM settlements # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Return the sum and average of all settlement amounts. # ### SQL: # # SELECT sum(settlement_amount) , avg(settlement_amount) FROM settlements # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the name of services that have been used for more than 2 times in first notification of loss. # ### SQL: # # SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING count(*) > 2 # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Which services have been used more than twice in first notification of loss? Return the service name. # ### SQL: # # SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING count(*) > 2 # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What is the effective date of the claim that has the largest amount of total settlement? # ### SQL: # # SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY sum(t2.settlement_amount) DESC LIMIT 1 # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the claim that has the largest total settlement amount. Return the effective date of the claim. # ### SQL: # # SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY sum(t2.settlement_amount) DESC LIMIT 1 # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # How many policies are listed for the customer named "Dayana Robel"? # ### SQL: # # SELECT count(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Dayana Robel" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Count the total number of policies used by the customer named "Dayana Robel". # ### SQL: # # SELECT count(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Dayana Robel" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What is the name of the customer who has the most policies listed? # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1 # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Which customer uses the most policies? Give me the customer name. # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1 # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What are all the policy types of the customer named "Dayana Robel"? # ### SQL: # # SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "Dayana Robel" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Tell me the types of the policy used by the customer named "Dayana Robel". # ### SQL: # # SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "Dayana Robel" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What are all the policy types of the customer that has the most policies listed? # ### SQL: # # SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1) # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # List all the policy types used by the customer enrolled in the most policies. # ### SQL: # # SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1) # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # List all the services in the alphabetical order. # ### SQL: # # SELECT service_name FROM services ORDER BY service_name # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Give me a list of all the service names sorted alphabetically. # ### SQL: # # SELECT service_name FROM services ORDER BY service_name # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # How many services are there? # ### SQL: # # SELECT count(*) FROM services # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Count the total number of available services. # ### SQL: # # SELECT count(*) FROM services # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the names of users who do not have a first notification of loss record. # ### SQL: # # SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Which customers do not have a first notification of loss record? Give me the customer names. # ### SQL: # # SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the names of customers who have used either the service "Close a policy" or the service "Upgrade a policy". # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" OR t3.service_name = "Upgrade a policy" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Which customers have used the service named "Close a policy" or "Upgrade a policy"? Give me the customer names. # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" OR t3.service_name = "Upgrade a policy" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the names of customers who have used both the service "Close a policy" and the service "New policy application". # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "New policy application" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Which customers have used both the service named "Close a policy" and the service named "Upgrade a policy"? Give me the customer names. # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "New policy application" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the IDs of customers whose name contains "Diana". # ### SQL: # # SELECT customer_id FROM customers WHERE customer_name LIKE "%Diana%" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What are the IDs of customers who have "Diana" in part of their names? # ### SQL: # # SELECT customer_id FROM customers WHERE customer_name LIKE "%Diana%" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What are the maximum and minimum settlement amount on record? # ### SQL: # # SELECT max(settlement_amount) , min(settlement_amount) FROM settlements # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Find the maximum and minimum settlement amount. # ### SQL: # # SELECT max(settlement_amount) , min(settlement_amount) FROM settlements # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # List all the customers in increasing order of IDs. # ### SQL: # # SELECT customer_id , customer_name FROM customers ORDER BY customer_id ASC # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What is the ordered list of customer ids? # ### SQL: # # SELECT customer_id , customer_name FROM customers ORDER BY customer_id ASC # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # Retrieve the open and close dates of all the policies associated with the customer whose name contains "Diana" # ### SQL: # # SELECT t2.date_opened , t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "%Diana%" # ### End.
insurance_fnol	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customers ( Customer_ID, Customer_name ) # Services ( Service_ID, Service_name ) # Available_Policies ( Policy_ID, policy_type_code, Customer_Phone ) # Customers_Policies ( Customer_ID, Policy_ID, Date_Opened, Date_Closed ) # First_Notification_of_Loss ( FNOL_ID, Customer_ID, Policy_ID, Service_ID ) # Claims ( Claim_ID, FNOL_ID, Effective_Date ) # Settlements ( Settlement_ID, Claim_ID, Effective_Date, Settlement_Amount ) # # Customers_Policies.Policy_ID can be joined with Available_Policies.Policy_ID # Customers_Policies.Customer_ID can be joined with Customers.Customer_ID # First_Notification_of_Loss.Customer_ID can be joined with Customers_Policies.Customer_ID # First_Notification_of_Loss.Policy_ID can be joined with Customers_Policies.Policy_ID # First_Notification_of_Loss.Service_ID can be joined with Services.Service_ID # Claims.FNOL_ID can be joined with First_Notification_of_Loss.FNOL_ID # Settlements.Claim_ID can be joined with Claims.Claim_ID # ### Question: # # What are the open and close dates of all the policies used by the customer who have "Diana" in part of their names? # ### SQL: # # SELECT t2.date_opened , t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "%Diana%" # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # How many kinds of enzymes are there? # ### SQL: # # SELECT count(*) FROM enzyme # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the total count of enzymes? # ### SQL: # # SELECT count(*) FROM enzyme # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # List the name of enzymes in descending lexicographical order. # ### SQL: # # SELECT name FROM enzyme ORDER BY name DESC # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names of enzymes in descending order? # ### SQL: # # SELECT name FROM enzyme ORDER BY name DESC # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # List the names and the locations that the enzymes can make an effect. # ### SQL: # # SELECT name , LOCATION FROM enzyme # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names and locations of all enzymes listed? # ### SQL: # # SELECT name , LOCATION FROM enzyme # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the maximum Online Mendelian Inheritance in Man (OMIM) value of the enzymes? # ### SQL: # # SELECT max(OMIM) FROM enzyme # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the maximum OMIM value in the database? # ### SQL: # # SELECT max(OMIM) FROM enzyme # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the product, chromosome and porphyria related to the enzymes which take effect at the location 'Cytosol'? # ### SQL: # # SELECT product , chromosome , porphyria FROM enzyme WHERE LOCATION = 'Cytosol' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the product, chromosome, and porphyria of the enzymes located at 'Cytosol'? # ### SQL: # # SELECT product , chromosome , porphyria FROM enzyme WHERE LOCATION = 'Cytosol' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names of enzymes who does not produce 'Heme'? # ### SQL: # # SELECT name FROM enzyme WHERE product != 'Heme' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names of enzymes whose product is not 'Heme'? # ### SQL: # # SELECT name FROM enzyme WHERE product != 'Heme' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names and trade names of the medicines which has 'Yes' value in the FDA record? # ### SQL: # # SELECT name , trade_name FROM medicine WHERE FDA_approved = 'Yes' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names and trade names of the medcines that are FDA approved? # ### SQL: # # SELECT name , trade_name FROM medicine WHERE FDA_approved = 'Yes' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names of enzymes in the medicine named 'Amisulpride' that can serve as an 'inhibitor'? # ### SQL: # # SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names of the enzymes used in the medicine Amisulpride that acts as inhibitors? # ### SQL: # # SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the ids and names of the medicine that can interact with two or more enzymes? # ### SQL: # # SELECT T1.id , T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING count(*) >= 2 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # For every medicine id, what are the names of the medicines that can interact with more than one enzyme? # ### SQL: # # SELECT T1.id , T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING count(*) >= 2 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the ids, names and FDA approval status of medicines in descending order of the number of enzymes that it can interact with. # ### SQL: # # SELECT T1.id , T1.Name , T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the ids, names, and FDA approval status for medicines ordered by descending number of possible enzyme interactions? # ### SQL: # # SELECT T1.id , T1.Name , T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the id and name of the enzyme with most number of medicines that can interact as 'activator'? # ### SQL: # # SELECT T1.id , T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the id and name of the enzyme that can interact with the most medicines as an activator? # ### SQL: # # SELECT T1.id , T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the interaction type of the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'? # ### SQL: # # SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the type of interaction for the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'? # ### SQL: # # SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the most common interaction type between enzymes and medicine? And how many are there? # ### SQL: # # SELECT interaction_type , count() FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count() DESC LIMIT 1 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the most common types of interactions between enzymes and medicine, and how many types are there? # ### SQL: # # SELECT interaction_type , count() FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count() DESC LIMIT 1 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # How many medicines have the FDA approval status 'No' ? # ### SQL: # # SELECT count(*) FROM medicine WHERE FDA_approved = 'No' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # How many medicines were not approved by the FDA? # ### SQL: # # SELECT count(*) FROM medicine WHERE FDA_approved = 'No' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # How many enzymes do not have any interactions? # ### SQL: # # SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction ); # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the count of enzymes without any interactions? # ### SQL: # # SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction ); # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What is the id and trade name of the medicines can interact with at least 3 enzymes? # ### SQL: # # SELECT T1.id , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the ids and trade names of the medicine that can interact with at least 3 enzymes? # ### SQL: # # SELECT T1.id , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3 # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the distinct name, location and products of the enzymes which has any 'inhibitor' interaction? # ### SQL: # # SELECT DISTINCT T1.name , T1.location , T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the different names, locations, and products of the enzymes that are capable inhibitor interactions? # ### SQL: # # SELECT DISTINCT T1.name , T1.location , T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # List the medicine name and trade name which can both interact as 'inhibitor' and 'activitor' with enzymes. # ### SQL: # # SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activitor' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the medicine and trade names that can interact as an inhibitor and activitor with enzymes? # ### SQL: # # SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activitor' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # Show the medicine names and trade names that cannot interact with the enzyme with product 'Heme'. # ### SQL: # # SELECT name , trade_name FROM medicine EXCEPT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the medicine and trade names that cannot interact with the enzyme with the product 'Heme'? # ### SQL: # # SELECT name , trade_name FROM medicine EXCEPT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX' # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # How many distinct FDA approval statuses are there for the medicines? # ### SQL: # # SELECT count(DISTINCT FDA_approved) FROM medicine # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # How many different FDA approval statuses exist for medicines? # ### SQL: # # SELECT count(DISTINCT FDA_approved) FROM medicine # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # Which enzyme names have the substring "ALA"? # ### SQL: # # SELECT name FROM enzyme WHERE name LIKE "%ALA%" # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # What are the names of enzymes that include the string 'ALA'? # ### SQL: # # SELECT name FROM enzyme WHERE name LIKE "%ALA%" # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # find the number of medicines offered by each trade. # ### SQL: # # SELECT trade_name , count(*) FROM medicine GROUP BY trade_name # ### End.
medicine_enzyme_interaction	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # medicine ( id, name, Trade_Name, FDA_approved ) # enzyme ( id, name, Location, Product, Chromosome, OMIM, Porphyria ) # medicine_enzyme_interaction ( enzyme_id, medicine_id, interaction_type ) # # medicine_enzyme_interaction.medicine_id can be joined with medicine.id # medicine_enzyme_interaction.enzyme_id can be joined with enzyme.id # ### Question: # # How many medicines are offered by each trade name? # ### SQL: # # SELECT trade_name , count(*) FROM medicine GROUP BY trade_name # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # List all schools and their nicknames in the order of founded year. # ### SQL: # # SELECT school , nickname FROM university ORDER BY founded # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What are the different schools and their nicknames, ordered by their founding years? # ### SQL: # # SELECT school , nickname FROM university ORDER BY founded # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # List all public schools and their locations. # ### SQL: # # SELECT school , LOCATION FROM university WHERE affiliation = 'Public' # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What are the public schools and what are their locations? # ### SQL: # # SELECT school , LOCATION FROM university WHERE affiliation = 'Public' # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # When was the school with the largest enrollment founded? # ### SQL: # # SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Return the founded year for the school with the largest enrollment. # ### SQL: # # SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Find the founded year of the newest non public school. # ### SQL: # # SELECT founded FROM university WHERE affiliation != 'Public' ORDER BY founded DESC LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What is the founded year of the non public school that was founded most recently? # ### SQL: # # SELECT founded FROM university WHERE affiliation != 'Public' ORDER BY founded DESC LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # How many schools are in the basketball match? # ### SQL: # # SELECT count(DISTINCT school_id) FROM basketball_match # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Count the number of schools that have had basketball matches. # ### SQL: # # SELECT count(DISTINCT school_id) FROM basketball_match # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What is the highest acc percent score in the competition? # ### SQL: # # SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Return the highest acc percent across all basketball matches. # ### SQL: # # SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What is the primary conference of the school that has the lowest acc percent score in the competition? # ### SQL: # # SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Return the primary conference of the school with the lowest acc percentage score. # ### SQL: # # SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What is the team name and acc regular season score of the school that was founded for the longest time? # ### SQL: # # SELECT t2.team_name , t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Return the name of the team and the acc during the regular season for the school that was founded the earliest. # ### SQL: # # SELECT t2.team_name , t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Find the location and all games score of the school that has Clemson as its team name. # ### SQL: # # SELECT t2.All_Games , t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson' # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What are the all games score and location of the school called Clemson? # ### SQL: # # SELECT t2.All_Games , t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson' # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What are the average enrollment size of the universities that are founded before 1850? # ### SQL: # # SELECT avg(enrollment) FROM university WHERE founded < 1850 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Return the average enrollment of universities founded before 1850. # ### SQL: # # SELECT avg(enrollment) FROM university WHERE founded < 1850 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # Show the enrollment and primary_conference of the oldest college. # ### SQL: # # SELECT enrollment , primary_conference FROM university ORDER BY founded LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What are the enrollment and primary conference for the university which was founded the earliest? # ### SQL: # # SELECT enrollment , primary_conference FROM university ORDER BY founded LIMIT 1 # ### End.
university_basketball	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # basketball_match ( Team_ID, School_ID, Team_Name, ACC_Regular_Season, ACC_Percent, ACC_Home, ACC_Road, All_Games, All_Games_Percent, All_Home, All_Road, All_Neutral ) # university ( School_ID, School, Location, Founded, Affiliation, Enrollment, Nickname, Primary_conference ) # # basketball_match.School_ID can be joined with university.School_ID # ### Question: # # What is the total and minimum enrollment of all schools? # ### SQL: # # SELECT sum(enrollment) , min(enrollment) FROM university # ### End.

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